Question : One man or two women or three boys can do a piece of work in 88 days. One man, one woman, and one boy will do it in:
Option 1: 44 days
Option 2: 24 days
Option 3: 48 days
Option 4: 20 days
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Correct Answer: 48 days
Solution : Time taken by 1 man or 2 women or 3 boys to do work = 88 days Time taken by 1 man = 88 days Efficiency of 1 man = $\frac{1}{88}$ Efficiency of 1 man = efficiency of 2 women = efficiency of 3 boys Efficiency of 1 man, 1 woman, and 1 boy = $(1+\frac{1}{2}+\frac{1}{3})$ × efficiency of 1 man = $\frac{11}{6}$ × $\frac{1}{88}$ = $\frac{1}{48}$ Time taken by 1 man,1 woman, and 1 boy = 48 days Hence, the correct answer is 48 days.
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Question : The ratio of time taken to complete a work by a man and a woman is 2 : 3. The man and the woman can complete the work together in 24 days. In how many days can the woman complete the work alone?
Option 1: 20 days
Option 2: 40 days
Option 3: 60 days
Option 4: 30 days
Question : A work can be completed by 8 boys in 48 days. If 2 boys leave after working for 24 days, then how many days will be needed to complete the remaining work?
Option 3: 32 days
Question : Three men can complete a piece of work in 6 days. Two days after they started the work, 3 more men joined them. How many days will it take to complete the remaining work?
Option 1: 1 day
Option 2: 2 days
Option 3: 3 days
Option 4: 4 days
Question : 4 men and 8 women complete a job in 10 days and 5 men and 24 women complete the same work in 4 days. In how many days will 1 man and 1 woman complete the same work?
Option 1: $63 \frac{1}{3}$ days
Option 2: $69 \frac{7}{9}$ days
Option 3: $67 \frac{1}{3}$ days
Option 4: $62 \frac{2}{9}$ days
Question : 10 women can do a piece of work in 6 days, 6 men can do the same work in 5 days, and 8 children can do it in 10 days. What is the ratio of the efficiency of a woman, a man, and a child, respectively?
Option 1: 4 : 6 : 3
Option 2: 4 : 5 : 3
Option 3: 2 : 4 : 3
Option 4: 4 : 8 : 3
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