Matrix operations like addition, subtraction, and multiplication are the basic methods used to work with matrices in mathematics. These operations make it easier to solve problems and perform calculations involving rows and columns of numbers. In this article, we will learn about matrix addition, matrix subtraction, and matrix multiplication with simple explanations and examples used in mathematics.
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A matrix is a rectangular arrangement of numbers, symbols, or expressions written in rows and columns. It is a fundamental concept in linear algebra used to represent data, solve equations, and perform various mathematical operations.
Below is an example of a matrix structure of 3 rows and 4 columns:
$\left[\begin{array}{llll}a_{11} & a_{12} & a_{13} & a_{14} \\ a_{21} & a_{22} & a_{23} & a_{24} \\ a_{31} & a_{32} & a_{33} & a_{34}\end{array}\right]_{3 \times 4}$
In general form, the above matrix is represented by $A=\left[a_{i j}\right]$
$a_{11}$, $a_{12}$,.. etc. are called the elements of the matrix.
$a_{ij}$ belongs to the ith row and jth column and is called the $(i,j)$ th element of the matrix.
The addition, subtraction, and multiplication of matrices are the three basic algebraic matrix operations.
Matrix addition is a basic operation where two matrices of the same order are added by combining their corresponding elements. If $A = [a_{ij}]$ and $B = [b_{ij}]$ are two matrices of order $m \times n$, then their sum is
$A + B = [a_{ij} + b_{ij}]$
This means each element of the resulting matrix is obtained by adding the elements in the same position from $A$ and $B$.
For two matrices to be added:
Both must have the same order (same number of rows and columns).
Example: A $2 \times 3$ matrix can only be added to another $2 \times 3$ matrix.
Each element is added position-wise.
$(i, j)$-th element of the result = $a_{ij} + b_{ij}$.
Matrix addition follows these properties:
Commutative law: $A + B = B + A$
Associative law: $(A + B) + C = A + (B + C)$
Let $A = \begin{bmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \end{bmatrix}, \quad B = \begin{bmatrix} 6 & 5 & 4 \\ 3 & 2 & 1 \end{bmatrix}$
Step 1: Check if both matrices are of the same order.
$A$ and $B$ are both $2 \times 3$ matrices → valid for addition.
Step 2: Add corresponding elements:
$A + B = \begin{bmatrix} 1+6 & 2+5 & 3+4 \\ 4+3 & 5+2 & 6+1 \end{bmatrix}$
Step 3: Simplify each entry:
$A + B = \begin{bmatrix} 7 & 7 & 7 \\ 7 & 7 & 7 \end{bmatrix}$
Thus, the sum of matrices $A$ and $B$ is another $2 \times 3$ matrix where all entries are $7$.
Example:
$
\begin{aligned}
\mathrm{A} & =\left[\begin{array}{lll}
10 & 20 & 30 \\
20 & 30 & 40 \\
30 & 40 & 50
\end{array}\right], \quad \mathrm{B}=\left[\begin{array}{lll}
50 & 40 & 30 \\
40 & 30 & 20 \\
30 & 20 & 10
\end{array}\right] \\
\mathrm{A}+\mathrm{B} & =\left[\begin{array}{lll}
10+50 & 20+40 & 30+30 \\
20+40 & 30+30 & 40+20 \\
30+30 & 40+20 & 50+10
\end{array}\right]=\left[\begin{array}{lll}
60 & 60 & 60 \\
60 & 60 & 60 \\
60 & 60 & 60
\end{array}\right]
\end{aligned}
$
i) Matrix addition is commutative, A + B = B + A
ii) Matrix addition is associative, A + (B+C) = (A+B) + C
iii) Additive identity exists, which means there exists a matrix O (null matrix) such that A + O = A = O + A (Here O has the same order as A)
iv) Existence of additive inverse means there exists a matrix B such that A + B = O = B + A
v) Cancellation property: If A + B = A + C then B = C
If A + C = B + C then A = B
Note: All matrices taken in the above property explanation have the same order which is m × n.
Matrix subtraction is the process of subtracting corresponding elements of two matrices of the same order. If $A = [a_{ij}]$ and $B = [b_{ij}]$ are two matrices of order $m \times n$, then their difference is
$
\mathrm{A}=\left[\mathrm{a}_{\mathrm{ij}}\right]_{\mathrm{m} \times \mathrm{n}}, \mathrm{B}=\left[\mathrm{b}_{\mathrm{ij}}\right]_{\mathrm{m} \times \mathrm{n}} \text { Then, } \mathrm{A}-\mathrm{B}=\left[\mathrm{a}_{\mathrm{ij}}-\mathrm{b}_{\mathrm{ij}}\right]_{\mathrm{m} \times \mathrm{n} \text { for all } \mathrm{i}, \mathrm{j}}
$
Both matrices must have the same order.
Example: A $3 \times 2$ matrix can only be subtracted from another $3 \times 2$ matrix.
Subtraction is done element-wise:
$(i,j)$-th element of result = $a_{ij} - b_{ij}$.
Matrix subtraction is not commutative:
$A - B \neq B - A$ (in general).
Subtraction is related to addition:
$A - B = A + (-B)$, where $-B$ is the negative of matrix $B$.
Example:
$A = \begin{bmatrix} 5 & 7 \\ 2 & 4 \end{bmatrix}, \quad B = \begin{bmatrix} 1 & 3 \\ 6 & 2 \end{bmatrix}$
Then
$A - B = \begin{bmatrix} 5-1 & 7-3 \\ 2-6 & 4-2 \end{bmatrix} = \begin{bmatrix} 4 & 4 \\ -4 & 2 \end{bmatrix}$
$
\begin{aligned}
\mathrm{A} & =\left[\begin{array}{lll}
10 & 20 & 30 \\
20 & 30 & 40 \\
30 & 40 & 50
\end{array}\right], \quad \mathrm{B}=\left[\begin{array}{lll}
50 & 40 & 30 \\
40 & 30 & 20 \\
30 & 20 & 10
\end{array}\right] \\
\mathrm{A}-\mathrm{B} & =\left[\begin{array}{lll}
10-50 & 20-40 & 30-30 \\
20-40 & 30-30 & 40-20 \\
30-30 & 40-20 & 50-10
\end{array}\right]=\left[\begin{array}{ccc}
-40 & -20 & 0 \\
-20 & 0 & 20 \\
0 & 20 & 40
\end{array}\right]
\end{aligned}
$
i) Matrix subtraction is not commutative, $A-B \neq B-A$
ii) Matrix subtraction is not associative, $A-(B-C) \neq(A-B)-C$
iii) Cancellation property:
If A - B = A - C then B = C
If A - C = B - C then A = B
Note: All matrices taken in the above property explanation have the same order which is m × n.
Matrix multiplication is a fundamental operation where rows of the first matrix are multiplied with columns of the second matrix. If $A$ is of order $m \times n$ and $B$ is of order $n \times p$, then their product $C = AB$ is of order $m \times p$, where each element is defined as:
$c_{ij} = \sum_{k=1}^{n} a_{ik} \cdot b_{kj}$
Row by Column Multiplication
Standard matrix multiplication.
Possible only when the number of columns in $A$ equals the number of rows in $B$.
Example: If $A$ is $2 \times 3$ and $B$ is $3 \times 2$, then $AB$ is $2 \times 2$.
Scalar Multiplication
Each element of a matrix is multiplied by a scalar (a constant number).
If $k$ is a scalar and $A = [a_{ij}]$, then $kA = [k \cdot a_{ij}]$.
Order rule: If $A$ is $m \times n$ and $B$ is $n \times p$, then $AB$ is $m \times p$.
Matrix multiplication is not commutative: $AB \neq BA$ (in general).
It is associative: $(AB)C = A(BC)$.
It is distributive: $A(B+C) = AB + AC$.
Example 1: Row by Column Multiplication
$A = \begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}, \quad B = \begin{bmatrix} 2 & 0 \\ 1 & 3 \end{bmatrix}$
Step 1: Multiply row of $A$ with column of $B$:
$AB = \begin{bmatrix} 1 \cdot 2 + 2 \cdot 1 & 1 \cdot 0 + 2 \cdot 3 \\ 3 \cdot 2 + 4 \cdot 1 & 3 \cdot 0 + 4 \cdot 3 \end{bmatrix}$
Step 2: Simplify:
$AB = \begin{bmatrix} 4 & 6 \\ 10 & 12 \end{bmatrix}$
Example 2: Scalar Multiplication
If $k = 3$ and $A = \begin{bmatrix} 1 & -2 \\ 0 & 5 \end{bmatrix}$,
then
$3A = \begin{bmatrix} 3 & -6 \\ 0 & 15 \end{bmatrix}$
Let us understand about the types of matrices in detail with supporting examples.
Let $\mathrm{k}$ be any scalar number, and $A=\left[a_{i j}\right]_{m \times n}$ be a matrix. Then the matrix is obtained by multiplying every element $\mathrm{A}$ by a scalar $\mathrm{k}$ and denoted as kA.
$
\begin{aligned}
& k A=\left[k a_{i j}\right]_{m \times n} \\
& \qquad \mathrm{~A}=\left[\begin{array}{ll}
2 & 6 \\
3 & 7 \\
5 & 8
\end{array}\right] \text { then, } 3 \mathrm{~A}=\left[\begin{array}{ll}
3 \times 2 & 3 \times 6 \\
3 \times 3 & 3 \times 7 \\
3 \times 5 & 3 \times 8
\end{array}\right]=\left[\begin{array}{cc}
6 & 18 \\
9 & 21 \\
15 & 24
\end{array}\right]
\end{aligned}
$
If $A$ and $B$ are two matrices and $k, l$ are scalar then
i) $k(A+B)=k A+k B$
ii) $k l(A)=k(I A)=l(k A)$
iii) $(k+I) A=k A+I A$
iv) $(-k) A=-(k A)=k(-A)$
v) $1 \mathrm{~A}=\mathrm{A},(-1) \mathrm{A}=-\mathrm{A}$
Note: $A$ and $B$ have the same order $m \times n$.
Product AB can be found if the number of columns in matrix A and the number of Product $A B$ can be found if the number of columns in matrix $A$ and the number of rows in matrix B are equal. Otherwise, multiplication AB is not possible.
i) $A B$ is defined only if $\operatorname{col}(A)=\operatorname{row}(B)$
ii) $B A$ is defined only if $\operatorname{col}(B)=\operatorname{row}(A)$
If $\begin{aligned} & \mathrm{A}=\left[\mathrm{a}_{\mathrm{ij}}\right]_{\mathrm{m} \times \mathrm{n}} \\ & \mathrm{B}=\left[\mathrm{b}_{\mathrm{ij}}\right]_{\mathrm{n} \times \mathrm{p}} \\ & \mathrm{C}=\mathrm{AB}=\left[\mathrm{c}_{\mathrm{ij}}\right]_{\mathrm{m} \times \mathrm{p}} \\ & \text { Where } c_{\mathrm{ij}}=\sum_{\mathrm{j}=1}^{\mathrm{n}} \mathrm{a}_{\mathrm{ij}} \mathrm{b}_{\mathrm{jk}}, 1 \leq \mathrm{i} \leq \mathrm{m}, 1 \leq \mathrm{k} \leq \mathrm{p} \\ & =a_{i 1} b_{1 k}+a_{i 2} b_{2 k}+a_{i 3} b_{3 k}+\ldots+a_{i n} b_{n k} \\ & \end{aligned}$
i) Multiplication may or may not be commutative, so AB may or may not be equal to BA.
ii) Matrix multiplication is associative, meaning $A(B C)=(A B) C$
iii) Matrix multiplication is distributive over addition, mean $A(B+C)=A B+A C$ and $(B+C) A=B A+C A$
iv) If matrix multiplication of two matrices gives a null matrix then it doesn't mean that any of those two matrices was a null matrix.
Example:
$
A=\left[\begin{array}{ll}
0 & 2 \\
0 & 0
\end{array}\right] \text { and } B=\left[\begin{array}{ll}
1 & 0 \\
0 & 0
\end{array}\right] \text {, then } A B=\left[\begin{array}{ll}
0 & 0 \\
0 & 0
\end{array}\right]
$
v) Matrix multiplication $A \times A$ is represented by $A^2$. Thus, $A \cdot A \cdot A \cdot A \ldots \ldots . . n$ times $=A^n$.
vi) if $A$ is $m \times n$ matrix then, $I_m A=A=A I_n$.
Solution:
As the orders of the matrices A and B are the same $(2 \times 3)$, we can add them
$
\begin{aligned}
& A+B=\left[\begin{array}{rrr}
-3+4 & 2+1 & 4+5 \\
8+1 & 3+0 & 4+2
\end{array}\right] \\
& A+B=\left[\begin{array}{lll}
1 & 3 & 9 \\
9 & 3 & 6
\end{array}\right]
\end{aligned}
$
Hence, the value of
$
A+B \text { is }\left[\begin{array}{lll}
1 & 3 & 9 \\
9 & 3 & 6
\end{array}\right]
$
Solution:
As the order of both matrices are same $(2 \times 3)$, we can subtract them
$
\begin{aligned}
& A=\left[\begin{array}{lll}
8 & 6 & 5 \\
5 & 6 & 1
\end{array}\right], B=\left[\begin{array}{lll}
5 & 3 & 4 \\
2 & 4 & 0
\end{array}\right] \\
& A-B=\left[\begin{array}{lll}
8-5 & 6-3 & 5-4 \\
5-2 & 6-4 & 1-0
\end{array}\right] \\
& A-B=\left[\begin{array}{lll}
3 & 3 & 1 \\
3 & 2 & 1
\end{array}\right]
\end{aligned}
$
Hence, the value of
$
A-B \text { is }\left[\begin{array}{lll}
3 & 3 & 1 \\
3 & 2 & 1
\end{array}\right]
$
Example 3: If $\mathrm{X}$ and $\mathrm{Y}$ are two matrices such that
$
X+2 Y=\left[\begin{array}{ll}
5 & 2 \\
8 & 9
\end{array}\right]_{\text {and }}
$
$X-Y=\left[\begin{array}{cc}2 & -1 \\ 2 & 0\end{array}\right]$, then find the matrix $\mathbf{Y}$.
Solution:
Subtract both the given matrices
$
\begin{aligned}
& (X+2 Y)-(X-Y)=\left[\begin{array}{ll}
5 & 2 \\
8 & 9
\end{array}\right]-\left[\begin{array}{cc}
2 & -1 \\
2 & 0
\end{array}\right] \\
& \Rightarrow 3 Y=\left[\begin{array}{ll}
3 & 3 \\
6 & 9
\end{array}\right] \\
& \Rightarrow Y=\left[\begin{array}{ll}
1 & 1 \\
2 & 3
\end{array}\right]
\end{aligned}
$
Hence, the matrix $\mathrm{Y}$ is $\left[\begin{array}{ll}1 & 1 \\ 2 & 3\end{array}\right]$
Example 4: Which of the following ordered matrices A allow the addition A+A'=B
1) $A_{2\times 3}$
2) $A_{3\times 2}$
3) $A_{3\times 3}$
4) $A_{1\times 2}$
Solution:
Addition of Matrices -
Only matrices of the same order can be added or subtracted
When A has order 3x3, A' has order 3x3 as well.
Hence, the answer is option 3.
Matrix operations are related with several important concepts in linear algebra that extend their use in problem solving. Below are the key topics related to matrix operations.
NCERT resources are very helpful for understanding matrix operations in Class 12 Mathematics. They provide clear explanations, solved examples, and practice questions for better exam preparation. Below are the key NCERT resources for Chapter 3 – Matrices.
NCERT Class 12 Maths Notes for Chapter 3 - Matrices
NCERT Solutions for Class 12 Maths for Chapter 3 - Matrices
NCERT Exemplar Class 12 Maths Solutions for Chapter 3 - Matrices
Practice questions are essential to strengthen your understanding of matrix operations like addition, subtraction, and multiplication. They help in applying concepts and improving problem-solving speed. Below are practice questions and MCQs based on matrix operations.
Matrix Operations - Practice Question MCQ
You can practice questions on the related topics using the links shared below:
Frequently Asked Questions (FAQs)
Matrix calculus extends differential calculus to matrix-valued functions. It's crucial in optimization problems, especially in machine learning, where it's used to derive gradient descent algorithms, backpropagation in neural networks, and in understanding the behavior of loss functions in high-dimensional spaces.
Matrix multiplication can represent systems of linear equations compactly. If AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the constant matrix, this represents a system of linear equations. Solving for X is equivalent to solving the system.