Sticking Of Person With The Wall Of Rotor

Sticking Of Person With The Wall Of Rotor

Vishal kumarUpdated on 02 Jul 2025, 06:52 PM IST

Have you ever seen an object fly off a spinning merry-go-round or tried to hold a book fixed on a rotating table? These everyday occurrences manifest rather interesting dynamics of objects on a rotating platform. Skidding-unfastening of objects- forwards and sideways- is both amusing and hazardous, depending on the situation. In this paper, we will be engaged in understanding the physics of objects skidding on moving platforms in the line of duty which involves friction, centripetal force, and inertia, among others. In furtherance to this, we will discuss some related practical implications such as how objects can be secured on a moving surface and what principle keeps rotating machines and amusement rides securely in place. In this article, we will cover the concept of Skidding of Object on a Rotating Platform. This concept falls under the broader category of laws of motion.

Sticking Of Person With The Wall Of Rotor
Sticking Of Person With The Wall Of Rotor

Skidding of Object on a Rotating Platform

Centrifugal force ≤ Force of friction mω2r≤μmg∴ωmax=μgr= It is the maximum angular velocity of rotation of the platform so that the object will not skid on it. ω= Angular velocity r= radius μ= coefficient of friction

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Solved Examples Based on Sticking of Person With the Wall of Rotor

Example 1: As shown in the figure, a person of mass 'm' remains stuck to the wall of the rotating rotor. What should be the minimum value of angular velocity ω [coefficient of friction between wall and man is μ]


1) μgR
2) gR
3) gμR
4) μgR

Solution:

Sticking of Person with the wall of Rotor(Death well)


F= weight of person (mg)μR=mgμFc=mgμmωmin2r=mg∴ωmin=gμr Where F= friction force Fc= centrifugal force ωmin= minimum angular velocity μ= coefficient of friction r= radius of Rotor

From the figure


fr=mgμN=mg[fr=μN]μFc=mg[AsN=Fc]μmωmin2R=mg⇒ωmin=gμR

Hence, the answer is the option (3).

Example 2: A man is resting against the inner wall of a rotor which is moving with angular velocity ω. If the radius of the rotor is 2m and the coefficient of static friction between the wall and the person is 0.2. Find the minimum angular velocity (in rad/sec) for man to be at rest. (g= 10m/s2)

1) 5

2) 8

3) 10

4) 15

Solution

Sticking of Person with the wall of Rotor(Death well)

F = weight of person (mg)

μR=mgμFc=mgμmωmin2r=mg∴ωmin=gμr

wherein

F = friction force

Fc = centrifugal force

Wmin = minimum angular velocity

μ=coefficient of friction

r = radius of Rotor



N=mw2Rfs=μN=μmw2R
For the Resting position of the person

:fs=mg⇒μm2R=mgμω2R=gω2=gμR⇒100.2×2=25ω=5rad/sec

Hence, the answer is the option (1).

Example 3: A person stands in contact against the inner wall of a rotor of radius r. The coefficient of friction between the wall and the clothing is μ and the rotor is rotating about a vertical axis. What is the minimum angular speed of the rotor so that the person does not slip downward?

1) gμr
2) gμ
3) 2gμr
4) 1μr

Solution:

For the circular motion of the person
N=mrω2
Now for the vertical motion of the person

f=fmax=μNf=μmrω2

We also know f=mg

μmrω2=mgω=gμr

Hence, the answer is the option (1).

Example 4: A man of 50 pounds was made to stand against the inner wall of a hollow cylinder and the rotor of radius 5m is rotating at its vertical axis, and the coefficient of friction between the wall and his clothing is 0.35. What is the minimum angular speed of the rotor so that the person does not slip downward?

1) 2rads−1
2) 6rads−1
3) 5rads−1
4) 0.3rads−1

Solution:

The cylinder is in a vertical position. The normal reaction of the wall on man acts horizontally and it is equal to the centripetal force acting on it.

R=mrω2

Then the frictional force acts upward

F=mg

The man will still remain stuck to the wall after the floor is removed he will continue to rotate with the cylinder
μ≥FRF≤μRmg≤μmrω2ω2≤gμRω≤gμR
The minimum angular speed of rotation

ω=gμRμ=0.35,r=5 m,g=9.8 m/s2ω=9.80.35×5ω=2.31rads−1=2rads−1

Hence, the answer is the option (1).
Summary
Skidding on a rotating platform might happen since the frictional force between that object and the platform may not be sufficient to produce the needed centripetal force to keep it in its curved path. Because the platform rotates, the centripetal force pulls the object toward the centre. However, should the friction become too low because of a very smooth surface, large speed, or a heavy mass of the object, then the inertia of the object will just slide it outward. This very effect is what makes things slide off a lazy Susan and what keeps people safe on amusement park rides where they would skid if not for the safety features built into their ride. Something must be done in order to ensure adequate friction to keep things from skidding. Non-slip surfaces or proper tethering of objects will do the trick. Knowing these concepts a rotating platform or ride can be designed and run much safer from accident.

Frequently Asked Questions (FAQs)

Q: How does the rotor experiment demonstrate the concept of mechanical equilibrium?
A:
The rotor demonstrates mechanical equilibrium when the person remains stationary relative to the rotating wall. At this point, the centripetal force provided by the wall, friction, and the person's weight are in balance, resulting in no net force in the rotating frame of reference.
Q: What would happen if the rotor's radius changed while spinning?
A:
If the rotor's radius increased while spinning at a constant angular velocity, the centripetal force on the person would increase, making them feel more pressed against the wall. If the radius decreased, they would feel less force. This demonstrates the relationship between radius and centripetal force.
Q: How does the rotor experiment relate to the concept of escape velocity?
A:
While not directly related, both involve overcoming a central force. In the rotor, the rotational speed must be high enough for the centripetal force to overcome gravity. Similarly, escape velocity is the speed needed for an object to overcome a planet's gravitational pull.
Q: What would happen if the rotor was spinning in a vacuum?
A:
If the rotor was spinning in a vacuum, the basic principles would remain the same. The main difference would be the absence of air resistance, which could allow for higher rotational speeds. The person inside would still stick to the wall due to centripetal force.
Q: How does the rotor experiment relate to the formation of accretion disks in space?
A:
The rotor experiment demonstrates principles similar to those in accretion disk formation. In both cases, material is held in a circular path by a central force (the rotor wall or gravity), and friction plays a role in the system's behavior.
Q: What would happen if the person in the rotor tried to throw an object?
A:
If a person in the spinning rotor threw an object, its path would appear curved from their perspective due to the Coriolis effect. From an outside view, the object would move in a straight line tangent to the circle at the point it was released, demonstrating inertia.
Q: Can the principles of the rotor be used to separate mixtures?
A:
Yes, this principle is used in centrifuges to separate mixtures. By rotating at high speeds, denser components experience a stronger centrifugal effect and move farther from the axis of rotation, while less dense components stay closer to the center.
Q: How does the concept of centripetal acceleration apply to the rotor?
A:
Centripetal acceleration is the change in velocity needed to keep an object moving in a circular path. In the rotor, this acceleration is constantly directed towards the center of rotation. Its magnitude is proportional to the square of the angular velocity and the radius of the rotor.
Q: Can the principles of the rotor be applied to design safer vehicles?
A:
Yes, understanding centripetal force is crucial in vehicle design, especially for cornering. Car suspensions and tire designs are optimized to provide the necessary centripetal force for turning without skidding, similar to how the rotor's wall provides force to keep the person in place.
Q: How does the rotor experiment demonstrate Newton's First Law of Motion?
A:
The rotor experiment demonstrates Newton's First Law by showing that an object (the person) tends to continue in a straight-line motion unless acted upon by an external force. The wall of the rotor provides this force, constantly changing the person's direction to keep them in circular motion.