Work is one of the most fundamental concepts in physics and forms the foundation of topics like energy and power. In everyday life, work means any physical activity, but in physics, work has a precise meaning. Work is said to be done when a force acts on a body and produces displacement. The amount of work done depends on three important factors: the magnitude of force, the displacement of the object, and the angle between force and displacement. The SI unit of work is joule (J), and its dimensional formula is ML²T⁻². Understanding the work done formula, variation with angle, and practical examples is essential for Class 9 and 11 Physics, especially in the chapter Work, Energy and Power.
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In everyday language, work means doing any physical or mental activity. For example, walking, lifting a bag, or pushing a table is commonly called work. However, in physics, the meaning of work is more specific.
In physics, work is said to be done only when a force is applied to an object and the object moves (displacement occurs). If there is no movement, then no work is done, even if you feel tired.
For example, pushing a wall does not count as work in physics if the wall does not move.
The standard definition of work done states:
"Work done by a force is equal to the dot product of the force applied and the displacement of the body."
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If a body is applied by some amount of force F and the body covers some displacement S then the work done by the body is written mathematically as W=F.S where W is denoted for work done.

S.I Unit of Work Done
The S.I unit of work is joule (J).
One joule of work is said to be done when a force of one newton moves a body through a distance of one metre in the direction of the force.
$
1 \text { Joule }=1 \text { Newton } \times 1 \text { metre }
$
Thus,
$
1 J=1 N \cdot m
$
Although newton-metre $(N \cdot m)$ is equal to joule, the term joule is preferred for work to avoid confusion with torque.
Dimensional Formula of Work Done
Work $=$ Force × Displacement
We know,
Dimensional formula of Force $=$ MLT $^{-2}$
Dimensional formula of Displacement $=\mathbf{L}$
Therefore,
Dimensional formula of Work $=\mathbf{M L}^{\mathbf{2}} \mathbf{T}^{\mathbf{- 2}}$
Consider a block lying horizontally on the table and now it’s affected by some amount of applied force in a particular direction F and let this block gets moved to some displacement in specific direction S and the angle between the force vector and the displacement vector be then the work done by the body in order to cover this displacement is defined as W=F.S and since it’s the dot product between force vector and displacement vector so, Work done is written as W=FScos

Hence, the meaning of work done is simply that, the amount of work done by a body in order to cover a displacement of S when applied with some force of magnitude F and having an angle between force and displacement vector is calculated as W=FScos
Various Factors on which Work done by a body depends.
Some of the factors which affect the work done by a body are listed as:
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Work done by a force depends on the angle $(\theta)$ between the force vector and the displacement vector.
The formula of work done is:
$
W=F S \cos \theta
$
Since work is proportional to $\boldsymbol{\operatorname { c o s }} \boldsymbol{\theta}$, its value changes as the angle $\theta$ changes.
We know that:
$\cos 0^{\circ}=1$
$\cos 90^{\circ}=0$
$\cos 180^{\circ}=-1$
As the angle increases from $0^{\circ}$ to $90^{\circ}$, the value of $\cos \theta$ decreases from 1 to 0 . Therefore, work done decreases.
Different Cases
1. When $0^{\circ} \leq \theta<90^{\circ}$
Work done is positive because $\cos \theta$ is positive.
Example: Pulling a cart forward.
2. When $\theta=0^{\circ}$
Work done is maximum.
$
W=F S \cos 0^{\circ}=F S
$
Force and displacement are in the same direction.
3. When $\theta=90^{\circ}$
Work done is zero.
$
W=F S \cos 90^{\circ}=0
$
Force and displacement are perpendicular.
Example: Centripetal force in circular motion.
4. When $90^{\circ}<\theta \leq 180^{\circ}$
Work done is negative because $\cos \theta$ is negative.
Example: Friction acting opposite to motion.
Also Read:
In physics, work is done when a force is applied on a body and the body moves in the direction of the force. Some common examples are:
Also check-
NCERT Physics Notes:
Frequently Asked Questions (FAQs)
In physics, work done by a body is simply the amount of energy it needs to cover some displacement, and mathematically work done is defined as the dot product between force vector and displacement vector which is further written as W=F.S . For example, if a body is acted by some amount of force having magnitude F and body covers some displacement having magnitude S and the angle between force and displacement is then, the amount of work done performed by the body will be W=FScos
Work done by a body is simply defined as the product of the force applied on the body and displacement covered by the body, here we have given that F=8N and S=5m and work done is W=FS on putting the values, we get W=8×5=40Joules hence, work done by the body is 40J.
Mathematically, work done is defined as the dot product between force vector and displacement vector, and it’s written as, work done be W=FScos now, the nature of work meaning is that, if the value of cos is positive then the nature of work done will be positive and is the value of cos is negative, then the nature of work done will be negative. As well as if the force vector and displacement vector are perpendicular to each other, then the nature of work done will be zero.
The frictional force acts between two bodies between the surface of contact between them, and frictional force opposes the relative motion between two bodies in contact so, the frictional force is opposing force, hence if the body moves forward so friction force will act in the opposite direction which is backward hence, the angle between the friction force vector and displacement vector is always θ=180° which makes work done by frictional force always negative as W=FScos180°=-FS Hence, work done by the frictional force is always negative.
Since work done is the product between force vector and displacement vector between two bodies. And the force of gravity acts on an object in a downward direction towards the ground and if a block is moving horizontally on the ground then, it covers displacement in a horizontal direction whereas the force of gravity acts in a vertically downward direction, which makes the force of gravity vector and displacement vector perpendicular to each other which makes work done by the moving block is zero as W=FScos90°=0 Hence, work done by force of gravity is zero.
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