Pi-complex coordination compounds are a class of chemical species formed through the interaction of transition metal ions with pi-electron systems, such as alkenes, alkynes, and aromatic compounds. The metal complex of these compounds has the ability to coordinate with the pi-electron of the ligands which results in unique electronic and spectroscopic properties. This complex has significance in both theoretical and in practical aspects.
These are the compounds of metals with alkenes, alkynes, benzene, and other ring compounds. In these complexes, the metal and ligand form a bond that involves the π electrons of the ligand. Three common examples are Zeise's salt, ferrocene, and dibenzene chromium. These are shown in the figure below:
Zeise' salt Ferrocene Dibenzene chromium
The number of carbon atoms bound to the metal in these compounds is indicated by the Greek letter 'η' with a number. The prefixes η2, η5, and η6 indicate 2, 5, and 6 carbon atoms are involved in the formation of the bond with the metal atom in the compound.
In bonding involves both the sigma-donation from the ligands and pi-bonding from the metal which enhances the stability of the complex
pi-complex are generally very stable and the stability is influenced by the factors such as the nature of the metal, the pi-ligand, and the environment of the complex.
In general the presence of the presence of unpaired electrons in the pi-complex can lead to paramagnetism. The magnetic can also be influenced by the electronic configuration of the central metal atoms and nature of ligands.
Example 1
Question: Among the given complexes, identify the one(s) which is/are also (pi)-complex(es):
(a) Zeise's salt
(b) Ferrocene
(c) Dibenzene Chromium
d) none
Solution: Zeise's salt, Ferrocene, and Dibenzene Chromium are all (pi)-complexes. These complexes involve the metal-ligand bond formation by the donation of (pi) electrons from the ligands to the metal.
Hence, the correct answer is Option (4): (a), (b), and (c).
Example 2
Question:The sum of bridging carbonyls in W(CO)6 and Mn2(CO)10 is ______________
a) 0
b) 3
c) 1
d) 2
Solution:
W(CO)6 has 0 bridging CO groups.
Mn2(CO)10) also has 0 bridging CO groups.
Thus, the sum of bridging carbonyls in both complexes is 0.
Hence, the correct answer is Option (1): 0.
Example 3
Question: Given below are two statements: one is labeled as “Assertion A” and the other is labelled as “Reason R”
- Assertion A: In the complex Ni(CO)4 and Fe(CO)5, the metals have zero oxidation state.
- Reason R: Low oxidation states are found when a complex has ligands capable of (pi)-donor character in addition to the (sigma)-bonding.
In the light of the above statements, choose the most appropriate answer from the options given below:
1) A is not correct but R is correct.
2) A is correct but R is not correct.
3) Both A and R are correct and R is the correct explanation of A.
4) Both A and R are correct but R is NOT the correct explanation of A.
Solution:
Statement A is correct as the metals have zero oxidation state in both Ni(CO)4 and Fe(CO)5.
Statement R is incorrect because ligands must have (sigma)-donor and (pi)-acceptor characters for the metal to exhibit a low oxidation state.
Hence, the most appropriate answer is Option (2): A is correct but R is not correct.
Example 4
Question: Which among the following complexes has the metal in the highest oxidation state?
(a) [Cr(CO)6
(b) [Mn(CO)5Br]
(c) Fe(CO)5
(d) [Co(CO)4]
Solution:
Cr(CO)6): Chromium is in the 0 oxidation state.
[Mn(CO)5Br]: Manganese is in the +1 oxidation state due to the presence of a bromide ion.
Fe(CO)5): Iron is in the 0 oxidation state.
[Co(CO)4]: Cobalt is in the 0 oxidation state.
The complex [Mn(CO)5Br] has the metal in the highest oxidation state of +1.
Hence, the correct answer is Option (b):[Mn(CO)5Br]
Example 5
Question: Identify the complex where the metal exhibits the highest coordination number:
(a) [Fe(CO)5]
(b) [Co(NH3)6]3+
(c) [PtCl4]2-
(d) {[Cr(en)3]3+
Solution:
[Fe(CO)5]): Iron has a coordination number of 5.
[Co(NH3)6]3+): Cobalt has a coordination number of 6.
[PtCl4]2-: Platinum has a coordination number of 4.
[Cr(en)3]3+): Chromium has a coordination number of 6 (each ethylenediamine (en) ligand counts as 2 due to its bidentate nature).
The complexes [Co(NH3)6]3+)) and [Cr(en)_3]3+ both have the highest coordination number of 6.
Hence, the correct answer is Option (b) and (d): [Cr(en)3]3+) and [Cr(en)3]3+).
The study of pi-complex coordination compounds is vital in various fields, which include material science catalysis, and bioinorganic chemistry, they have a very important role in the olefination, hydrogenation, and polymerization. The pi-complex has a great contribution to the field of coordination chemistry such as in the ligand field theory and also in the bonding.
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