Valence Bond Theory of Coordination Compounds

Valence Bond Theory of Coordination Compounds

Shivani PooniaUpdated on 02 Jul 2025, 07:42 PM IST

The Valence Bond Theory is the basis upon which a very delicate interaction between metal ions and ligands is represented. The central metal atom or ion is surrounded by molecules or ions called ligands. One of the most important concepts of VBT arises from the ability of the ligand to donate electron pairs to the metal center, thereby forming coordinate bonds.

This Story also Contains

  1. Interpretation of Coordination Compounds According to VBT
  2. Weaknesses of VBT
  3. Some Solved Examples
  4. Summary
Valence Bond Theory of Coordination Compounds
Valence Bond Theory of Coordination Compounds


Interpretation of Coordination Compounds According to VBT

According to this theory, the metal atom or ion under the influence of ligands can use its (n-1)d or nd orbitals along with its ns and np for hybridization to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral, square planar and so on. These hybridized orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. The different types of hybridization and their respective shapes are given below

Coordination NumberType of HybridisationShape
4sp3Tetrahedral
4dsp2Square Planar
5sp3dTrigonal Bipyramidal
6sp3d2Octahedral
6d2sp3Octahedral

Let us consider the case of [Ni(CN)4]2+ and try to predict the hybridization of this complex

Here nickel is in a +2 oxidation state and the ion has a valence electronic configuration 3d84s

In the presence of Cyanide ions, the electrons will be paired up and the hybridization of Ni in the complex will bed sp2 as shown below


Each of the hybridized orbitals receives a pair of electrons from a cyanide ion. The compound is diamagnetic as evident from the absence of unpaired electrons.

Weaknesses of VBT


While the Valence Bond theory, to a larger extent, explains the formation, structures, and magnetic behavior of coordination compounds, it has some shortcomings which are listed below:
(i) It involves several assumptions.
(ii) It does not give a quantitative interpretation of magnetic data.
(iii) It does not explain the color exhibited by coordination compounds.
(iv) It does not give a quantitative interpretation of the thermodynamic or kinetic stabilities of coordination compounds.
(v) It does not make exact predictions regarding the tetrahedral and square planar structures of 4-coordinate complexes.
(vi) It does not distinguish between weak and strong ligands.

Recommended topic video on(Valence Bond Theory of Coordination Compounds)



Some Solved Examples

Example 1
Question:

The molecule in which hybrid molecular orbitals involve only one d-orbital of the central atom is:

1)[Ni(CN)4]2−
2) BrF5
3)XeF4
4)[CrF6]3−

Solution

Hybridization of the given molecules-

(1)[Ni(CN)4]2−→dsp2
(2)BrF5−Sp3 d2
(3)XeF4−Sp3 d2
(4)(CrF6)3−−d2Sp3

So, in [Ni(CN)4]2− molecule hybrid MOs involve only one d-orbital of the central atom.

Therefore, the correct option is (1).

Example 2
Question:

According to the valence bond theory, the hybridization of a central metal atom is dsp2 for which one of the following compounds?

1)NiCl2⋅6H2ONiCl2⋅6H2O

2)K2[Ni(CN)4] K2[Ni(CN)4]

3)[Ni(CO)4][Ni(CO)4]

4)Na2[NiCl4]Na2[NiCl4]

Solution

Configuration of Ni=[Ar]4s23d8
Configuartion of Ni2+=[Ar]3d8

Thus, Ni2+ has 2 unpaired electrons which can be paired up in the presence of a strong field ligand like CN-as depicted below

Thus, [Ni(CN)4]2− has a dsp2 hybridisation.
Hence, the correct answer is option (2).

Example 3
Question:

In Wilkinson’s catalyst, the hybridization of the central metal ion and its shape are respectively :

1) sp3d, trigonal bipyramidal
2) sp3 tetrahedral
3) dsp2,square planar
4) d2sp3octahedral

Solution:

As we learned in

Hybridization -

sp3d2 - square bipyramidal or octahedral

d2sp3 - octahedral

sp3 - tetrahedral

dsp2 - square planar

wherein

sp3d2 - outer complex

d2sp3 - inner complex

sp3−[Ni(Cl)4]2− dsp2−[Pt(CN)4]2−

sp3−[Ni(Cl)4]2dsp2−[Pt(CN)4]2−

The Wilkinson catalyst is [RhCl(pph3)3] and the hybridization and its shape are dsp2and square planar respectively.

Hence, the answer is an option (3).

Example 4
Question:

Identify the pair in which the geometry of the species is T-shape and square-pyramidal, respectively :

1)ClF3 and IO4-
2)ICl2-and ICl5
3) XeOF2and XeOF4
4)IO3-and IO2F2-

Solution:

As we learned in

Structure of XeOF2 -

Sp3d hybridized and T-shaped structure

- wherein



Structure of Xenon XeOF4 (oxytetrafluoride) -

Sp3d2 hybridized and square pyramidal structure

- wherein



Summary

In a nutshell, the Valence Bond Theory is maybe one of the most important tools in knowing the bonding and properties of coordination compounds, overhead in scientific and industrial use. In short, VBT describes how the metal ion interacts with ligands to form stable complexes while taking their geometrical arrangement on the principles of hybridization. This theory focuses on the level of strength of a ligand and the hybridization types that give rise to a diversity of structures, instituting tetrahedral and square planar geometries.

Frequently Asked Questions (FAQs)

Q: What is the role of molecular orbital theory in complementing Valence Bond Theory for coordination compounds?
A:
Molecular Orbital Theory complements VBT by providing a more comprehensive description of bonding in coordination compounds. While VBT focuses on localized bonds, MO theory considers the formation of molecular orbitals across the entire complex. This helps explain phenomena that VBT struggles with, such
Q: How does Valence Bond Theory explain the concept of ligand substitution reactions?
A:
VBT explains ligand substitution reactions by considering changes in hybridization and orbital overlap. The process involves breaking existing metal-ligand bonds and forming new ones, which VBT describes through changes in the hybridization scheme of the metal and new orbital overlaps with incoming ligands.
Q: What is the significance of sd hybridization in coordination compounds?
A:
sd hybridization, while less common, is significant in explaining some linear complexes, particularly those involving transition metals in low oxidation states. It involves one s-orbital and one d-orbital of the metal, resulting in two hybrid orbitals arranged linearly. This can occur in certain d9 complexes.
Q: How does Valence Bond Theory account for the Irving-Williams series?
A:
VBT doesn't directly explain the Irving-Williams series, which is a limitation. The series describes the relative stability of complexes formed by divalent first-row transition metals. While VBT can describe the bonding in each complex, it doesn't inherently predict the trend in stability observed in the series.
Q: How does Valence Bond Theory explain the concept of lability and inertness in coordination compounds?
A:
VBT explains lability and inertness by considering the strength and nature of metal-ligand bonds. Labile complexes have weaker metal-ligand bonds, often due to poor orbital overlap or competing interactions. Inert complexes have stronger bonds, typically due to effective orbital overlap and stable electronic configurations.
Q: How does Valence Bond Theory explain the formation of bent complexes?
A:
VBT explains bent complexes through sp2 hybridization of the metal's orbitals. Three hybrid orbitals are formed, with two used for bonding to ligands and one containing a lone pair. This results in a bent geometry, as seen in complexes like [Cu(NH3)2]+, where the bond angle is less than 180°.
Q: What is the significance of dsp3 hybridization in coordination compounds?
A:
dsp3 hybridization is significant in forming trigonal bipyramidal complexes. It involves one d-orbital, one s-orbital, and three p-orbitals of the metal, resulting in five hybrid orbitals arranged in a trigonal bipyramidal geometry. This hybridization is seen in five-coordinate complexes like PCl5.
Q: How does Valence Bond Theory account for the nephelauxetic effect?
A:
VBT doesn't directly account for the nephelauxetic effect, which is the expansion of d-orbitals in complexes compared to the free ion. However, VBT's consideration of covalent bonding between metal and ligands indirectly relates to this effect, as increased covalency leads to greater orbital expansion.
Q: What is the role of steric factors in Valence Bond Theory of coordination compounds?
A:
Steric factors in VBT influence the preferred geometry and stability of complexes. Bulky ligands can affect the hybridization scheme by favoring geometries that minimize steric repulsion. VBT considers these factors when explaining why certain complexes adopt specific structures or exhibit particular properties.
Q: What is the significance of f-orbital involvement in Valence Bond Theory of coordination compounds?
A:
f-orbital involvement in VBT is significant for explaining the bonding in lanthanide and actinide complexes. While less common, f-orbitals can participate in hybridization schemes, leading to unique geometries and properties. This expands VBT's applicability to a wider range of elements beyond transition metals.