Imagine driving around a curve and feeling a pull outward that's centripetal acceleration in action, an important concept in circular motion. It helps explain how Forces work on a vehicle during turns. Understanding this can make driving safer, especially when navigating curves at higher speeds. In this report, we explore the role of centripetal acceleration, factors that affect it like speed and friction, and practical tips for handling turns. In this article we will be studying the centripetal acceleration derivation. This concept, covered in Class 11 Physics under circular motion, derivation of centripetal acceleration is essential for board exams and competitive exams like JEE Main, NEET, BITSAT, and others. Between 2013 and 2023, five questions on this topic have appeared in JEE Main.
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Centripetal acceleration is the acceleration of a body moving in a circular path, which is always directed towards the centre of the circle. It is responsible for continuously changing the direction of the velocity of the body, thereby keeping it in circular motion.
Even if the speed of the body remains constant, its velocity changes due to the change in direction, and hence acceleration is produced. This acceleration is called centripetal acceleration.
The magnitude of centripetal acceleration depends on the speed of the body and the radius of the circular path. It is given by:
$
a=\frac{v^2}{r}
$
Consider a body of mass ‘m’ moving on the circumference of a circle of radius ‘r’ with a velocity ‘v’. A force F is then applied to the body. And this force is given by
F = ma


Where, a= acceleration which is given by the rate of change of velocity with respect to time.
Consider the triangles $\triangle O A B$ and $\triangle P Q R$, then:
$
\Delta v_{A B}=\frac{v}{r}
$
Clearly, from the diagram (not shown here), the arc length $A B=v \Delta t$.
Now, we have:
$
\frac{\Delta v}{v \Delta t}=\frac{v}{r}
$
Simplifying this:
$
\frac{\Delta v}{\Delta t}=\frac{v^2}{r}
$
Thus, the centripetal acceleration equation is:
$
a=\frac{v^2}{r}
$
Note: The direction of centripetal acceleration(& force) is towards the centre of the circle.
Now, let's move to another part of this article which is Centripetal Force
The direction of centripetal acceleration and also force is towards the centre of the circle.
Centripetal acceleration is widely used to understand and explain circular motion in physics and real life. Some important uses are:
| Centripetal Acceleration | Tangential Acceleration |
| Acts towards the center of the circular path | Acts along the tangent to the path |
| Changes the direction of velocity | Changes the magnitude (speed) of velocity |
| Present in all circular motion | Present only when speed is changing |
| Formula: $( a_c = \frac{v^2}{r} )$ | Formula: $( a_t = \frac{dv}{dt} )$ |
| Responsible for keeping object in circular path | Responsible for speeding up or slowing down |
Q.1 A car moves in a circular path of radius $\mathbf{2 0 ~ m}$ with a speed of $\mathbf{1 0 ~ m} / \mathbf{s}$.
Find its centripetal acceleration.
Solution:
Using formula,
$
\begin{gathered}
a_c=\frac{v^2}{r} \\
a_c=\frac{(10)^2}{20}=\frac{100}{20}=5 \mathrm{~m} / \mathrm{s}^2
\end{gathered}
$
Centripetal acceleration $=5 \mathrm{~m} / \mathrm{s}^2$.
Q.2 A stone tied to a string rotates in a horizontal circle of radius 0.5 m with an angular speed of 6 rad/s. Calculate centripetal acceleration.
Solution:
Using formula,
$
\begin{gathered}
a_c=\omega^2 r \\
a_c=(6)^2 \times 0.5=36 \times 0.5=18 \mathrm{~m} / \mathrm{s}^2
\end{gathered}
$
Centripetal acceleration $=18 \mathrm{~m} / \mathrm{s}^2$.
Q.3 A fan blade rotates with an angular speed of $\mathbf{2 0 ~ r a d} / \mathrm{s}$. If the edge of the blade is $\mathbf{0 . 3 ~ m}$ from the centre, find the centripetal acceleration of the tip.
Solution:
$
\begin{gathered}
a_c=\omega^2 r \\
a_c=(20)^2 \times 0.3=400 \times 0.3=120 \mathrm{~m} / \mathrm{s}^2
\end{gathered}
$
Centripetal acceleration $=120 \mathrm{~m} / \mathrm{s}^2$.
Also, check-
Frequently Asked Questions (FAQs)
Centripetal acceleration is the acceleration of a body moving in a circular path, directed towards the centre of the circle. It is responsible for continuously changing the direction of the velocity of the object and keeping it in circular motion. Even if the speed remains constant, this acceleration exists because the direction of motion is changing.
centripetal acceleration,
a=v2/r
Where v = velocity, and r = radius
The force responsible for producing centripetal acceleration is called the centripetal force.
Derivation for centripetal force is given in this article.
The unit of centripetal acceleration is ms-2