Series RC Circuit

Series RC Circuit

Vishal kumarUpdated on 02 Jul 2025, 05:58 PM IST

A Series RC circuit consists of a resistor (R) and a capacitor (C) connected in series, forming a fundamental component in electrical and electronic systems. When an AC voltage is applied, the circuit demonstrates unique behaviours in terms of charging and discharging the capacitor, as well as impedance. These characteristics are pivotal in various practical applications such as filtering signals, shaping waveforms, and timing circuits. In everyday life, series RC circuits are found in devices like audio equipment, where they help manage signal frequencies, and in-camera flashes, where they control the charging time of the flash capacitor. In this article, we will understand the dynamics of a Series RC circuit is essential for designing and optimizing electronic devices and systems.

This Story also Contains

  1. Series RC Circuit
  2. Important Points
  3. Solved Examples Based on Series RC Circuit
  4. Example 1: The susceptance of a circuit is
  5. Summary
Series RC Circuit
Series RC Circuit

Series RC Circuit

A Series RC circuit is a simple electrical circuit that comprises a resistor (R) and a capacitor (C) connected in series with each other. This type of circuit is widely used in various electronic applications due to its ability to store and release energy, filter signals, and create time delays.

The above figure shows a circuit containing a resistor and capacitor connected in series through a sinusoidal voltage source voltage which is given by

$V=V_0 \sin (\omega t+\varphi)$

Now, in this case, the voltage across the resistor is VR=IR

And, the voltage across the capacitor is

$V_c=\frac{I}{\omega C}$

As we have studied in the previous concept the VR is in phase with current I and VC lags behind I by a phase angle $90^{\circ}$

The above figure is the phase diagram of this case. So, the V is the resultant of $V_R$ and $V_C$. So we can write

$
\begin{aligned}
V & =\sqrt{V_R^2+V_C^2} \\
& =i \sqrt{R^2+\frac{1}{\omega^2 C^2}} \\
& =i Z
\end{aligned}
$
where,
$
\begin{gathered}
Z=\sqrt{R^2+\frac{1}{\omega^2 C^2}} \\
i=\frac{V}{Z}=\frac{V}{\sqrt{R^2+X_c^2}}=\frac{V}{\sqrt{R^2+\frac{1}{4 \pi^2 \nu^2 c^2}}}
\end{gathered}
$

Here, Z is the impedance of this circuit.

Now, from the phasors diagram, we can see that the applied voltage lags behind the current by a phase angle φ given by

$tan \varphi = \frac{V_C}{V_R} = \frac{1}{\omega CR}$

Important Points

1. Capacitive susceptance $\left(S_C\right)$

Capacitive susceptance, denoted as BC, is a measure of how easily an AC circuit with a capacitor can pass alternating current. It is the imaginary part of the admittance (Y) in an AC circuit, analogous to how resistance is the real part of the impedance. While impedance (Z) opposes the flow of current, susceptance facilitates it. In a capacitive circuit, susceptance is positive and is given by the reciprocal of capacitive reactance (XC).

$\begin{aligned} & S_C=\frac{1}{X_c}=\omega C \\ & \omega C=2 \pi \nu C\end{aligned}$

2. Power factor

Power factor is a key parameter in electrical engineering that measures the efficiency of power usage in an AC electrical system. It is defined as the ratio of real power (P) to apparent power (S), where:

$
\text { Ratio }=\frac{\text { True Power }}{\text { Apprent power }}
$

So,
$
\cos \phi=\frac{R}{\sqrt{R^2+X_c^2}}
$

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Solved Examples Based on Series RC Circuit

Example 1: The susceptance of a circuit is

1) $\frac{1}{R}$
2) $\frac{1}{Z}$
3) $\frac{1}{X}$
4) None

Solution:

Susceptance is a measure of how easy it is for alternating current to pass through a capacitance or an inductance. Susceptance is the imaginary part of admittance, whose real part is conductance, which is the inverse of resistance. So conductance, Susceptance, or Admittance, all have the same unit ohm-1

Susceptance (S) -The reciprocal of reactance.

$S=\frac{1}{X}$

Hence, the answer is the option (3).

Example 2: Calculate the susceptance (S) in a given circuit.

1) $\frac{1}{\pi}$
2) $\frac{2}{\pi}$
3) $\pi$
4) $2 \pi

Solution:

Capacitive susceptance SC

$\begin{aligned} & S_C=\frac{1}{X_c}=\omega L \\ & \omega L=2 \pi \nu C \\ & \text { Susceptance } S=\frac{1}{\text { rectance }}=\frac{1}{X_C} \\ & \begin{aligned} \therefore S & =\omega C \\ & =(2 \pi \times 50) \times 10^{-2} \\ & =\pi\end{aligned}\end{aligned}$

Hence, the answer is the option (3).

Example 3: For the LCR circuit, shown here, the current is observed to lead to the applied voltage. An additional capacitor C', when joined with the capacitor C present in the circuit, makes the power factor of the circuit unity. The capacitor C', must have been connected in :

1) series with C and has a magnitude $\frac{1-\omega^2 L C}{\omega^2 L}$
2) series with C and has a magnitude $\frac{C}{\left(\omega^2 L C-1\right)}$
3) parallel with C and has a magnitude $\frac{C}{\left(\omega^2 L C-1\right)}$
4) parallel with C and has a magnitude $\frac{1-\omega^2 L C}{\omega^2 L}$

Solution:

Power factor

The ratio of resistance and impedance $(\cos \phi)$.
After inserting $c /$ both become equal since
$
\cos \phi=\frac{R}{Z}=1
$
or $R^2=R^2+\left(X_L-X_C\right)^2$
$
=>X_L=X_C------2
$

This implies must reduced
This will happen when C is increased.
$\therefore C^{\prime}$ must be inserted in parallel to $C$.
$
\begin{aligned}
& \therefore \omega L=\frac{1}{\omega\left(C+C^{\prime}\right)} \\
& \text { or } C+C^{\prime}=\frac{1}{\omega^2 L \text { or }} C^{\prime}=\frac{1}{W^2 L}-C \\
& \text { or } C^{\prime}=\frac{1-\omega^2 L C}{\omega^2 L}
\end{aligned}
$

Hence, the answer is the option (4).

Example 4: Calculate the power factor for a given circuit

1) 0.012

2) 0.24

3) 0.028

4) 0.16

Solution:

Power factor

$
\cos \phi=\frac{R}{Z}
$
wherein
$
\begin{aligned}
& R \rightarrow \text { resistance } \\
& Z \rightarrow \text { impedance }
\end{aligned}
$

Power factor
$
\cos \phi=\frac{R}{Z}
$

In the given circuit

$\begin{aligned} & R=0.1 \Omega \\ & Z=\sqrt{R^2+\left(X_L-X_C\right)^2} \\ & X_L=\omega L=(2 \pi \times 50) \times 10^{-2}=\pi \\ & X_C=\frac{1}{\omega C}=\frac{1}{100 \pi \times 10^{-2}}=\frac{1}{\pi} \\ & Z=\sqrt{(0.1)^2+\left(\pi-\frac{1}{\pi}\right)^2}=8 \Omega \\ & \quad \Rightarrow \cos \phi=\frac{0.1}{8}=0.012\end{aligned}$

Hence, the answer is the option (1).

Example 5: Power factor is defined as the ratio of

$\begin{aligned} & \text { 1) } \frac{\text { Apparent Power }}{\text { True Power }} \\ & \text { 2) } \frac{\text { Instantaneous Power }}{\text { Apparent Power }} \\ & \text { 3) } \frac{\text { Instantaneous Power }}{\text { True Power }} \\ & \text { 4) } \frac{\text { True Power }}{\text { Apparent Power }}\end{aligned}$

Solution:

Power factor

$\begin{aligned} & \text { Ratio }=\frac{\text { True Power }}{\text { Apparent power }} \\ & \text { Power factor }=\frac{\text { True Power }}{\text { Apparent power }}\end{aligned}$

Hence, the answer is option (4).

Summary

A Series RC circuit, consisting of a resistor and a capacitor in series, is fundamental in various electronic applications due to its ability to filter signals, store and release energy, and create time delays. Key concepts include capacitive susceptance, which measures how easily an AC circuit with a capacitor passes alternating current, and power factor, which indicates the efficiency of power usage in an AC system. Understanding these principles helps in designing and optimizing electronic devices and systems, ensuring efficient power usage and performance.

Frequently Asked Questions (FAQs)

Q: What is the significance of the phase angle in power calculations for series RC circuits?
A:
The phase angle in a series RC circuit determines the power factor and the relationship between real and reactive power. A larger phase angle means more reactive power and less real power for a given apparent power. This concept is crucial in power systems and in designing
Q: How does the concept of frequency-dependent voltage division apply to series RC circuits?
A:
In a series RC circuit, the voltage division between the resistor and capacitor depends on frequency. At low frequencies, most of the voltage appears across the capacitor, while at high frequencies, it's mostly across the resistor. This frequency-dependent behavior is fundamental to the circuit's filtering properties.
Q: What is the importance of understanding series RC circuits in the context of bioelectrical impedance analysis?
A:
In bioelectrical impedance analysis, used for body composition measurements, tissues are often modeled as combinations of resistors and capacitors. Understanding series RC circuits helps in interpreting the complex impedance of biological tissues, which varies with frequency due to the capacitive nature of cell membranes.
Q: What is the significance of the RC time constant in digital circuit applications?
A:
In digital circuits, the RC time constant is crucial for determining the rise and fall times of signals, affecting the maximum operating frequency of the circuit. It's important in debouncing switches, creating pulse width modulation signals, and in the design of analog-to-digital converters.
Q: How does the concept of power dissipation differ between the resistor and capacitor in a series RC circuit?
A:
In a series RC circuit, real power is dissipated only in the resistor, converting electrical energy to heat. The capacitor, ideally, does not dissipate power but instead stores and returns energy to the circuit. The capacitor is associated with reactive power, which oscillates between the capacitor and the source.
Q: What is the role of series RC circuits in creating time delays in electronic systems?
A:
Series RC circuits can create time delays due to the finite time required for the capacitor to charge or discharge. This property is used in timing circuits, pulse shaping, and in creating phase shifts in oscillator circuits. The delay is proportional to the time constant τ = RC.
Q: How does the concept of energy storage apply to series RC circuits?
A:
In a series RC circuit, energy is stored in the electric field of the capacitor. During each AC cycle, energy is transferred between the source and the capacitor, with some energy dissipated in the resistor. Understanding this energy flow is crucial for power analysis and efficiency considerations in AC circuits.
Q: How does temperature affect the behavior of a series RC circuit?
A:
Temperature changes can affect both the resistance and capacitance in a series RC circuit. Typically, resistance increases with temperature in most materials, while capacitance can increase or decrease depending on the dielectric material. These changes can alter the circuit's time constant, phase relationships, and frequency response.
Q: What is the importance of initial conditions in analyzing transient responses of RC circuits?
A:
Initial conditions, such as the initial charge on the capacitor or the initial current in the circuit, are crucial for accurately predicting the transient response of an RC circuit. They determine the starting point of the exponential charging or discharging curve and affect the time taken to reach steady state.
Q: How does a series RC circuit respond to a sudden change in voltage (step response)?
A:
When a step voltage is applied to a series RC circuit, the capacitor voltage rises exponentially towards the applied voltage, while the current starts at a maximum and decays exponentially to zero. The rate of this change is determined by the time constant τ = RC. This response is crucial in understanding switching behavior in electronic circuits.