Have you ever wondered why the number of atoms on both sides of a chemical equation must be the same? What would happen if we didn’t balance an equation? Would it break the laws of nature? We will get these answers after reading this article on balancing a chemical equation. When the reactant and product sides of an equation have the same number of each element, the equation is balanced
To accurately depict the rule of conservation of mass, equations must be balanced. The inclusion of Stoichiometric coefficients for the reactants and products is required to balance chemical equations. This is crucial because a chemical equation must follow the laws of conservation of mass and constant proportions,
A chemical equation is a symbol for a chemical reaction in which the reactants and products are represented by their chemical formulae.
$2 \mathrm{H}_2+\mathrm{O}_2 \rightarrow 2 \mathrm{H}_2 \mathrm{O}$ is an example of a chemical equation that depicts the reaction between Hydrogen and oxygen to generate water.
The part of the chemical equation to the left of the ‘→' sign is the reactant side, while the part to the right of the arrow symbol is the product side.
The total number of molecules of a chemical species that participate in a chemical reaction is described by a stoichiometric coefficient.
It calculates the ratio between the responding species and the reaction products.
The stoichiometric coefficients of O2 and H2O in the reaction $\mathrm{CH}_4+2 \mathrm{O}_2 \rightarrow \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O}$ are 2 and 1, respectively, in the equation $\mathrm{CH}_4+2 \mathrm{O}_2 \rightarrow \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O}$.
Stoichiometric coefficients are assigned in a way that balances the total number of atoms of an element on the reactant and product sides when balancing chemical equations.
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When it comes to balancing chemical equations, the first step is to acquire the entire imbalanced equation. The combustion process between propane and oxygen is used as an example to demonstrate this method.
Step 1: Create an unbalanced equation using the chemical formulae of the reactants and products (if it is not already provided).
The molecular formula for propane is C3H8. It creates carbon dioxide (CO2) and water when it comes into touch with oxygen (O2) (H2O).
$\mathrm{C}_3 \mathrm{H}_8+\mathrm{O}_2 \rightarrow 3 \mathrm{CO}_2+\mathrm{H}_2 \mathrm{O}$
Step 2: On the reactant and product sides, compare the total number of atoms of each element. In this situation, the number of atoms on each side can be tabulated as follows.
Chemical equation: $\mathrm{C}_3 \mathrm{H}_8+\mathrm{O}_2 \rightarrow 3 \mathrm{CO}_2+\mathrm{H}_2 \mathrm{O}$ | |
Reactant side |
Product side |
3 C from $\mathrm{C}_3 \mathrm{H}_8$ |
1 C from CO2 |
8 H From $\mathrm{C}_3 \mathrm{H}_8$ |
2 H from H2O |
2 O from O2 |
3 O, 2 from CO2 and 1 from H2O |
Step 3: On the reactant and product sides, stoichiometric factors are now applied to compounds containing an element with a specific number of atoms.
The coefficient must balance the number of atoms on each side.
The hydrogen and oxygen atoms' stoichiometric coefficients are normally assigned last.
It's time to adjust the number of atoms in the reactant and product elements.
It's important to note that the total number of atoms of an element in one molecule of a species is calculated by multiplying the stoichiometric coefficient by the total number of atoms of that element in that molecule.
When the CO2 molecule is assigned the coefficient 3, the total number of oxygen atoms in CO2 becomes 6. The coefficient is first assigned to in this case.
Chemical equation: $\mathrm{C}_3 \mathrm{H}_8+\mathrm{O}_2 \rightarrow 3 \mathrm{CO}_2+\mathrm{H}_2 \mathrm{O}$ | |
Reactant side |
Product side |
3 Carbon atoms from C3H8 |
3 Carbon atoms from CO2 |
8 Hydrogen atoms from C3H8 |
2 Hydrogen atoms from H2O |
2 Oxygen atoms from O2 |
7 Oxygen atoms, 6 from CO2 and 1 from H2O |
Step 4: Step 3 is repeated until the reactant and product sides of the reactive elements have the same number of atoms. In this scenario, hydrogen is balanced next. The chemical equation is altered in this manner.
Chemical equation: $\mathrm{C}_3 \mathrm{H}_8+\mathrm{O}_2 \rightarrow 3 \mathrm{CO}_2+\mathrm{H}_2 \mathrm{O}$ | |
Reactant side |
Product side |
3 C from C3H8 |
3 C from CO2 |
8 H from C3H8 |
8 H from H2O |
2 O from O2 |
10 O, 6 from CO2 and 4 from H2O |
Now that the hydrogen atoms are balanced, the next element to be balanced is oxygen. There are 10 oxygen atoms on the product side, implying that the reactant side must also contain 10 oxygen atoms.
Each O2 molecule contains 2 oxygen atoms. Therefore, the stoichiometric coefficient that must be assigned to the O2 molecule is 5. The updated chemical equation is tabulated below.
Chemical equation: $\mathrm{C}_3 \mathrm{H}_8+5 \mathrm{O}_2 \rightarrow 3 \mathrm{CO}_2+4 \mathrm{H}_2 \mathrm{O}$ | |
Reactant side |
Product side |
3 Carbon atoms from C3H8 |
3 Carbon atom from CO2 |
8 Hydrogen atoms from C3H8 |
8 Hydrogen atoms from H2O |
10 Oxygen atoms from O2 |
10 Oxygen atoms, 6 from CO2 and 4 from H2O |
Step 5: After all of the individual elements have been balanced, the total number of atoms in each element on the reactant and product sides is compared once more.
The chemical equation is said to be balanced if there are no inequalities.
Every element now has the same number of atoms on the reactant and product sides in this example.
As a result, $\mathrm{C}_3 \mathrm{H}_8+5 \mathrm{O}_2 \rightarrow 3 \mathrm{CO}_2+4 \mathrm{H}_2 \mathrm{O}$ is the balanced chemical equation.
EXAMPLE:
$\mathrm{Al}+\mathrm{O}_2 \rightarrow \mathrm{Al}_2 \mathrm{O}_3$ is an unbalanced chemical equation.
Traditional method
The reaction can be balanced using the old method as follows:
Chemical equation: $\mathrm{Al}+\mathrm{O}_2 \rightarrow \mathrm{Al}_2 \mathrm{O}_3$ | |
Reactant side |
Product side |
1 Aluminium atom |
2 Aluminum atoms |
2 oxygen atoms |
3 oxygen atoms |
The aluminium atoms are balanced first.
$\mathrm{Al}+\mathrm{O}_2 \rightarrow \mathrm{Al}_2 \mathrm{O}_3$
There are two oxygen atoms on the reactant side and three on the product side, so the oxygen atoms must be balanced now. As a result, there must be three O2 molecules that produce two Al2O3 atoms.
$2 \mathrm{Al}+3 \mathrm{O}_2 \rightarrow 2 \mathrm{Al}_2 \mathrm{O}_3$ is the chemical conversion equation.
Because the number of aluminium atoms on the product side has doubled, the number on the reactant side must have doubled as well
Chemical equation: $4 \mathrm{Al}+3 \mathrm{O}_2 \rightarrow 2 \mathrm{Al}_2 \mathrm{O}_3$ | |
Reactant side |
Product side |
4 Aluminium atoms |
4 Aluminum atoms |
6 oxygen atoms |
6 oxygen atoms |
Balanced chemical equation is found to be $2 \mathrm{Al}+3 \mathrm{O}_2 \rightarrow 2 \mathrm{Al}_2 \mathrm{O}_3$
Question.1 The number of moles of Br2 produced when two moles of potassium permanganate are treated with excess potassium bromide in an aqueous acid medium is:
1) 1
2) 3
3) 2
4) 4
Solution:
$
\mathrm{MnO}_4^{-}+\mathrm{Br}^{-} \rightarrow \mathrm{Br}_2+\mathrm{Mn}^{2+}
$
Oxidation half
$
\left[2 \mathrm{Br}^{-} \rightarrow \mathrm{Br}_2+2 e^{-}\right] \times 5
$
Reduction half
$
\left[\mathrm{SH}^{+}+\mathrm{MnO}_4^{-}+\mathrm{Se}^{-} \rightarrow \mathrm{Mn}^{+2}+4 \mathrm{H}_2 \mathrm{O}\right] \times 2
$
Adding both half reaction
$
\begin{gathered}
2 \mathrm{MnO}_4^{-}+10 \mathrm{Br}^{-}+16 \mathrm{H}^{+} \rightarrow 5 \mathrm{Br}_2+2 \mathrm{Mn}^{2+}+\mathrm{SH}_2 \mathrm{O} \\
2
\end{gathered}
$
2 moles of $\mathrm{MnO}_4^{-}$will produce 5 moles of $\mathrm{Br}_2$
Hence answer is 5 .
Hence, the answer is the option (2).
Question.2 In button cells widely used in watches, number of correct statements from the followings:
a) Redox reaction is observed.
b) 2 mole electrons are exchanged for 1 mole of $Z n$ metal
c) Ag is converted to $\mathrm{Ag}_2 \mathrm{O}$
d) $Z n$ is converted to $\mathrm{Zn}^{2+}$
Solution:
$
\mathrm{Zn}(s)+\mathrm{Ag}_2 \mathrm{O}(s)+\mathrm{H}_2 \mathrm{O}(l) \longrightarrow \mathrm{Zn}^{2+}+2 \mathrm{Ag}(\mathrm{~s})+2 \mathrm{OH}^{-}
$
2 mole $e^{-}$are utilized.
Redox reaction is observed.
2 mole electrons are exchanged for 1 mole of $Z n$ metal
$Z n$ is converted to $\mathrm{Zn}^{2+}$
Hence, the answer is (3).
Question.3 What is the number of electrons used in the reduction of 1mol of nitrate in the presence of acid?
1) 2
2) 5
3) 10
4) 9
Solution:
$
2 \mathrm{NO}^{-3}+10 \mathrm{e}^{-}+12 \mathrm{H}^{+} \rightarrow \mathrm{N}_2+6 \mathrm{H}_2 \mathrm{O}
$
Hence, the answer is option (3).
Practice More Question With The Link Given Below
Balancing of Redox Reaction: Ion Electrode Method practice question and MCQs |
Balancing of Redox Reaction: Oxidation Number Method practice question and MCQs |
Also check-
Ca(OH)2 + 2HNO3 → Ca(NO3)2 + 2H2O is the balanced chemical equation of the calcium hydroxide-nitric acid reaction.
A balanced chemical equation is one in which the number of atoms of each element in the reactants equals the number of atoms of that element in the products. This is necessary for the law of conservation of mass to be satisfied.
The number of molecules in a chemical species which participate in a chemical reaction is called its stoichiometric coefficient.
It calculates the ratio between the either sides of the chemical reaction.
C3H8 + 5O2 → 3CO2 + 4H2O
Balancing chemical equations is necessary to accurately represent chemical reactions. It also allows us to determine the stoichiometric relationships between the reactants and products, which can be useful for calculating the amount of reactants needed or the amount of products formed in a reaction.
The stoichiometric coefficients in a balanced chemical equation are determined by balancing the equation and ensuring that the number of atoms of each element is the same on both sides. The coefficients represent the ratios of the reactants and products in the reaction, so they must be in the lowest whole numbers possible.
Balancing chemical equations ensures that the law of conservation of mass is obeyed. It means that the number of atoms of each element must be equal on both sides of the equation, reflecting that matter is neither created nor destroyed in a chemical reaction.
Changing subscripts in chemical formulas would alter the identity of the compounds involved. Subscripts represent the ratio of atoms in a molecule, and changing them would create a different substance altogether. We only adjust the coefficients (numbers in front of formulas) when balancing.
The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. When balancing equations, we ensure that the number of atoms of each element is the same on both sides, reflecting this fundamental principle.
Coefficients are whole numbers placed in front of chemical formulas to indicate the number of molecules or formula units of that substance. They are adjusted during the balancing process to ensure equal numbers of atoms on both sides of the equation.
While it's possible to use fractional coefficients to balance an equation, it's generally preferred to use whole numbers. If you end up with fractions, multiply all coefficients by the least common denominator to convert them to whole numbers.
Reactants are the starting substances in a chemical reaction, written on the left side of the arrow. Products are the substances formed as a result of the reaction, written on the right side of the arrow. The arrow indicates the direction of the reaction.
The arrow in a chemical equation represents the direction of the reaction. It separates the reactants (on the left) from the products (on the right) and indicates that the reactants are being converted into the products.
State symbols (s, l, g, aq) indicate the physical state of each substance in the reaction. While they don't affect the balancing process, they provide important information about the conditions of the reaction and the nature of the substances involved.
A double arrow indicates a reversible reaction, where the products can convert back into reactants under certain conditions. When balancing, treat it like a single arrow equation, ensuring both forward and reverse reactions are balanced.
A catalyst is often written above the arrow in a chemical equation. It participates in the reaction but is neither consumed nor produced, so it doesn't affect the balancing process. However, it's important to note its presence in the equation.
Balancing equations is fundamental to stoichiometry, which deals with the quantitative relationships between reactants and products. A balanced equation provides the correct ratios of substances, allowing for calculations of amounts of reactants needed or products formed.
While limiting reactants don't affect the balancing process, a balanced equation is crucial for determining the limiting reactant. The balanced equation provides the stoichiometric ratios needed to calculate which reactant will be completely consumed first.
A skeleton equation shows the correct formulas of reactants and products but may not have the proper coefficients for balance. A balanced equation has the correct coefficients added to ensure equal numbers of atoms on both sides.
Balancing redox reactions is crucial because these reactions involve the transfer of electrons. Proper balancing ensures that the number of electrons lost by one species equals the number gained by another, maintaining electrical neutrality and mass conservation.
Many elements exist as diatomic molecules in their natural state (e.g., H₂, O₂, N₂). When balancing, remember to use the diatomic form in the equation. This often requires using even coefficients for these elements.
Half-reactions are separate equations showing the oxidation and reduction processes in a redox reaction. They are useful for balancing complex redox equations by allowing you to balance the oxidation and reduction parts separately before combining them.
The periodic table is crucial for identifying the elements in compounds and their properties. It helps in recognizing common oxidation states, which is particularly useful in balancing redox reactions and predicting products.
Nuclear equations are balanced differently from chemical equations. You must balance the mass numbers (total nucleons) and atomic numbers (protons) on both sides of the equation, often involving the emission or absorption of subatomic particles.
Oxidation numbers help identify which elements are being oxidized or reduced in a reaction. By tracking changes in oxidation numbers, you can determine how many electrons are transferred, which is crucial for balancing redox equations.
Combination reactions involve two or more reactants forming a single product, while decomposition reactions involve a single reactant breaking down into multiple products. The balancing process is similar, but the number of species on each side of the equation differs.
For combustion reactions, typically involving a hydrocarbon reacting with oxygen, start by balancing carbon, then hydrogen, and finally oxygen. Often, the products are carbon dioxide and water, which helps in identifying the general structure of the balanced equation.
Polyatomic ions often remain intact during reactions. When balancing, treat each polyatomic ion as a single unit. This can simplify the process, as you don't need to balance each atom within the polyatomic ion separately.
In ionic equations, the total charge on both sides must be equal. This is in addition to balancing the number of atoms. Failure to balance charge can result in an electrically imbalanced and physically impossible reaction.
More complex molecules with multiple elements can make balancing more challenging. It often requires a systematic approach, balancing one element at a time, starting with the element that appears in the fewest number of compounds.
For multi-step reactions, balance each step separately, then combine the balanced equations. Ensure that any intermediate products cancel out in the overall equation if they're not part of the final products.
Spectator ions are ions that don't participate in the reaction and appear unchanged on both sides of the equation. They can be omitted when writing net ionic equations, simplifying the balancing process.
A molecular equation shows all substances as molecules or compounds, while an ionic equation shows soluble ionic compounds as separated ions. Balancing an ionic equation requires considering individual ions, which can sometimes simplify the process.
For electrochemical cells, balance the half-reactions for oxidation and reduction separately, including electrons. Then combine the half-reactions, ensuring that the number of electrons lost equals the number gained.
A balanced equation provides the exact stoichiometric ratios of reactants and products. This is essential for calculating theoretical yields and determining the efficiency of a reaction by comparing actual yields to theoretical yields.
When products are unknown, use your knowledge of reaction types and the reactants involved to predict possible products. Then write a skeleton equation and balance it. Experimental data may be needed to confirm the actual products.
The coefficients in a balanced equation represent the mole ratios of the substances involved. These ratios are fundamental to stoichiometric calculations, allowing conversion between moles or masses of different substances in the reaction.
The algebraic method involves assigning variables to coefficients, writing equations based on the number of atoms of each element, and solving the resulting system of equations. This method is particularly useful for complex equations.
For reactions with fractional oxidation states, multiply the entire equation by the least common denominator of the fractions to eliminate them. Then proceed with balancing as usual, using whole number coefficients.
A balanced equation is essential for calculating reaction enthalpies and free energy changes. The coefficients in the balanced equation directly relate to the stoichiometric amounts used in thermochemical calculations.
Common mistakes include changing subscripts instead of coefficients, forgetting to balance all elements, overlooking diatomic molecules, and not verifying that the final equation is balanced. Always double-check your work.
Precipitates, usually denoted with (s) for solid, don't change the balancing process. However, recognizing precipitate formation is crucial for writing net ionic equations, where spectator ions can be eliminated.
Balanced equations provide the stoichiometric ratios needed to determine limiting reagents. By comparing the actual molar ratios of reactants to the ratios in the balanced equation, you can identify which reactant will be completely consumed first.
Treat complex ions as single units, similar to polyatomic ions. Balance the complex ion as a whole, then ensure that the individual atoms within the complex are also balanced across the equation.
Balanced equations are crucial in environmental chemistry for understanding and quantifying processes like acid rain formation, ozone depletion, and greenhouse gas emissions. They allow for accurate calculations of pollutant production and mitigation strategies.
In equilibrium reactions, the balanced equation represents the stoichiometric relationships at equilibrium. The coefficients in the balanced equation are used to write the equilibrium constant expression, a key tool in understanding reaction behavior.
In biochemistry, balanced equations are essential for understanding metabolic pathways, enzyme kinetics, and cellular energetics. They allow for quantitative analysis of complex biological processes and the flow of matter and energy in living systems.
The balancing process remains the same regardless of conditions. However, when dealing with gases, it's important to note that the coefficients in the balanced equation represent molar ratios, which can be converted to volume ratios using gas laws if needed.
Oxidation numbers help identify which species are being oxidized or reduced. By calculating the change in oxidation numbers, you can determine the number of electrons transferred, which is crucial for balancing redox equations, especially using the half-reaction method.
Balanced equations form the foundation of stoichiometry, which is used in various real-world applications such as industrial chemical production, pharmaceutical manufacturing, and environmental monitoring. It allows for precise calculations of reactant needs and product yields.
While a balanced equation shows the overall reaction, understanding reaction mechanisms often involves balancing multiple step-wise equations. This helps in identifying intermediates, transition states, and the detailed pathway of the reaction.
The presence of multiple phases (solid, liquid, gas, aqueous) doesn't change the balancing process. However, it's important to include phase labels (s, l, g, aq) in the final equation to provide a complete description of the reaction conditions.
In analytical chemistry, balanced equations are crucial for quantitative analysis, titrations, and instrumental methods. They allow for the calculation of concentrations, determination of unknown quantities, and validation of analytical procedures.
While rate laws are determined experimentally and may not directly correspond to the balanced equation, the balanced equation provides the foundation for understanding the reaction. It shows the stoichiometric relationships that inform initial hypotheses about rate laws.
In coupled reactions, where one reaction drives another, balancing each individual equation is crucial. The balanced equations allow for the analysis of how energy or electrons are transferred between the coupled processes, such as in ATP synthesis or electrochemical cells.
Microscopic reversibility states that the mechanism of a reverse reaction follows the exact reverse path of the forward reaction. When balancing equations, this principle ensures that if the forward reaction is balanced, the reverse reaction will also be balanced, which is particularly important in understanding equilibrium processes.