Have you ever wondered how ores are prepared before the extraction of metals? Why are some ores heated in the absence of air while others are heated in the presence of excess oxygen? What chemical changes occur during these heating processes, and how do they help in removing impurities from ores? The answers to these questions lie in two important metallurgical processes known as calcination and roasting, which play a crucial role in converting raw ores into forms suitable for metal extraction.
This Story also Contains
The calcination and roasting processes in the conversion of ore into its oxide are two important topics that will be discussed in this paper. Calcination involves the process of heating ore without air to remove the volatile substances, whereas roasting is termed a process by which ore is heated in excess oxygen to enhance the removal of sulfur and other impurities. These processes are followed to create pure metal of high grade for use in diverse industries.
Examples
Roasting is the heat treatment of ores in excess air to convert metals into their respective oxides and water-insoluble sulphides into water-soluble sulphates. It may, otherwise, be defined as a process for the deelectronation of ores, in which the process is centered on the removal of volatile impurities and the conversion of sulphide ores into the corresponding oxides. It essentially takes place in reverberatory furnaces.
Examples
Iron Sulfide In excess air, pyrite, $\mathrm{FeS}_2$, oxidizes to give iron oxide, $\mathrm{Fe}_2 \mathrm{O}_3$, and sulfur dioxide,
$\mathrm{SO}_2: \mathrm{FeS}_2 \rightarrow \mathrm{Fe}_2 \mathrm{O}_3+\mathrm{SO}_2$
The above process chain may merely be used as a way of changing the sulfide ore to a more reactive oxide form—the method also removes sulfur impurities.
Cinnabar Mercury ore- Roasting of cinnabar HgS, produces mercury oxide {HgO} and sulfur dioxide, $\mathrm{SO}_2$. The ore becomes an oxide; this makes the extraction of mercury more comfortable.
Zinc Sulfide Zinc sulfide ZnS is roasted to get zinc oxide {ZnO} and sulfur dioxide {$\mathrm{SO}_2$}. This method turns the sulfide ore into an oxide and makes it fit for further reduction.
Lead Sulphide {PbS} is roasted to yield lead oxide {PbO} and sulphur dioxide {$\mathrm{SO}_2$}. The processing of the ore into the oxide form makes it more reactive and thus easier for reduction to metallic lead.
Related Topics
Why are calcination and roasting considered essential steps in metallurgy? Their importance lies in the chemical and physical transformations they bring about in ores before metal extraction.
Significance:
Both processes help in converting ores into more reactive forms suitable for reduction.
They remove volatile impurities such as moisture, carbon dioxide, sulphur, and organic matter.
Calcination and roasting increase the porosity of ores, making subsequent extraction easier.
Roasting helps in oxidizing sulphide ores into oxides, which are easier to reduce.
Uses:
Calcination is used mainly for carbonate and hydrated ores like calamine (ZnCO₃) and bauxite.
Roasting is used for sulphide ores such as zinc blende (ZnS) and galena (PbS).
These processes are widely used in the extraction of metals like zinc, lead, iron, and copper.
They are also employed in industries such as cement manufacturing, lime production, and metallurgy.
Processes that are hugely fundamental to the courses for learners in Chemistry and Metallurgy, as in Material Science, Environmental Engineering, or Industrial Chemistry, since they assist in having an idea of the applications and the environmental impact caused by the extraction of the metals from their respective ores.
Also read :
Example 1:Which of the following factors is of no significance for roasting sulphide ores to the oxides and not subjecting the sulphide ores to carbon reduction directly?
1)CO2 is more volatile than CS2
2)Metal sulphides are thermodynamically more stable than CS2
3)CO2 is thermodynamically more stable than CS2
4) Metal sulphides are less stable than the corresponding oxides
Solution
The reduction of metal sulphides by carbon reduction is positive whereas, ΔG is negative for the same process with metal oxides. So, metal sulphides are more stable than oxides.
Hence, the statement given in Option 4 is incorrect:
"Metal sulphides are less stable than the corresponding oxides"
Hence, the answer is the option (4).
Example 2: The purest form of commercial iron is:
1) wrought iron
2)pig iron
3)scrap iron and pig iron
4)cast iron
Solution
The purest form of iron is wrought iron.
Hence, the answer is the option (1).
Example 3: The process that involves the removal of sulphur from the ores is :
1) Roasting
2)Leaching
3)Smelting
4)Refining
Solution
In the roasting process, metal sulphide (MS) ore is converted into metal oxide, and sulphur is removed in the form of SO2 gas
$2 \mathrm{MS}+3 \mathrm{O}_2\xrightarrow{\Delta}2 \mathrm{MO}+2 \mathrm{SO}_2 \uparrow$
Hence, the answer is the option (1).
Example 4: The carbon content in wrought iron is usually:
1) High, around 3-4%
2) Medium, around 2-3%
3) (correct) Low, less than 0.1%
4) High, around 8-10%
Solution:
Wrought iron has a low carbon content, typically less than $0.1 \%$, contributing to its malleability and ductility.
Hence, the answer is the option (3).
Practice more questions with the link given
Frequently Asked Questions (FAQs)
Volatilizing Frying,
Oxygen frying,
Frying sulfur.
Burning Without Oxygen is called pyrolysis. There, pyrolysis is a reaction to chemical decomposition that involves ranging from low to very low oxygen, or at least the insufficient oxygen required for heating.
In iron carbonates, a calcination process is performed to convert iron carbonates into carbon dioxides and iron oxides.
Calcination is sometimes called solid cleaning because the high temperature of the material used is used to remove the flexible material and other oxidizing part of the weight etc.