Hello, Kindly mention about what admit card is your query about so that we can help you further. If it is about IBPS then there may be a chance that a new admit card will be available if the correction occurred for more percent. But as long as your name is the same with initials as in the Identity card details you provided, you will be allowed in the exam hall.

Hope this helps.

Hello,

Firstly you can appear for CBSE board three times only.

So if you getting failed again and again there are plenty of other things for you.

Firstly you can take admission in NIOS board and do open schooling.

Second option you can do a diploma courses.

There are many options for in this you can do Computer Science related Diploma, medical diploma etc.

If you have failed in any subject you can reappear for that exam again.

Hopefully this helps!!

hi,

see there is no mandatory to give the details of latest marksheets as long as you meet all the criteria like age limit, qualification details, scores in any particular exam etc. however you did not mention whether the job is graduate level or 12th pass level. make sure all the academic details like 10th, 12th, graduation falls in consecutive orders.

hope you may understand.

Dear Candidate,

For the year 2021, the JEE Mains Exam is going to conduct in 4 sessions. Candidates have to fill only one application form of JEE Main 2021 for all the four sessions., but the application fees has to be paid depending on the number of sessions you want to appear.

If someone is unable to register in the february session, then there is no worry in it. NTA will reopen the application form window for the next sessions also. For more info, please visit the link given below.

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-application-form/amp

Hope it helps.

Hello dear aspirant,

You have to be present with your original documents at the time of college joining and reporting. Hopefully if you dont have the documents in your hand you will have to sumbit them within 15 days. But generally it depends on college management if they want to give you this time or not.

To qualify for JEE Mains 2021, Candidates who have passed Class 12 or equivalent exam in 2019, 2020 or those who will appear in 2021 are eligible. The Information Bulletin doesn't mention no.of attempts for JEE Mains per year. But for JEE Advanced, you should have appeared for your 12th either in 2020 or 2021. Because you are enquiring only about JEE Mains, you are eligible because you completed your 12th in 2019. You can check the Information Bulletin at: https://jeemain.nta.nic.in/webinfo2021/File/GetFile?FileId=1&LangId=P . And to qualify for JEE Mains 2021, Candidates who have passed Class 12 or equivalent exam in 2019, 2020 or those who will appear in 2021 are eligible. And the other criteria is that to qualify for JEE Mains, there is no minimum aggregate criteria. But if you want to join NITs, IIITs or CFTIs then you should score a minimum aggregate of 75% only in your 12th. 11th marks aren't considered. And then to appear for JEE Advanced which is the gateway for admission to IITs, you will need to fulfill the 75% aggregate condition. Now it is 75% for General Category and 65% for Reserved Categories. So how much you score in 12th is what matters to secure your eligibility for NITs, IIITs, CFTIs and JEE Advanced.

hey!

if the print option is occurring on  your window, try downloading the pages,  if there is any option to download the content. otherwise directly try using the shortkey "ctrl + p " or " ctrl + shift + p"  to print the pages. after using this short key , a dialogue box will apear to print out the pages.

Hope it helps, thankyou!

Hello,

If you fail your driving test, you must wait two weeks before you can take it again and pay the applicable retest fee. You have three chances to pass. If you fail three times, you have to start over in the licensing process.

Dear Candidate,

We know that, the rate of effusion is inversely proportional to molecular mass, i.e.

r1 / r2  = √ ( M2 / M1 )

And, the rate of effusion is ratio of the volume effused to the tima taken

i.e.  V1 * t2  / V2  * t1  = √ ( M2 / M1)

Since , the volume remains same we have

√ ( M2 / M1) = 3 and hence solving we get M2 = 36.

Hope it helps.

Hi Aspirant,

The certain gas which will take three times as long to effuse out as helium its molecular mass will be 36u since volume is same so 3/1 will be equal to root square of Mw2/4.On calculating the mass is 36u.This is based on calculations by basic formulas and it generally comes in 3-4 marks in exam.

Hope it helps!!