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Delhi University Joint Admission Test

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i am 12th humanities student and i wanna take attepmt of DU JAT can i give this exam without having math as a main subject........but for exam i can prepare my self

Tanya Gupta 12th Mar, 2024

Hello,

Yes, you can take the DU JAT even if you are a humanities student without math as your main subject. The DU JAT primarily tests your proficiency in Quantitative Ability, Reasoning and Analytical Ability, General English, and Business and General Awareness. While a background in mathematics may be helpful

13 Views

Question : Rahul sold a box for INR 1,440 at a loss of 40%. What should the selling price of the box be to enable Rahul to earn a profit of 40%?

Option 1: INR 2,592

Option 2: INR 3,480

Option 3: INR 3,120

Option 4: INR 3,360

Team Careers360 21st Jan, 2024

Correct Answer: INR 3,360


Solution : Selling price = INR 1,440
Loss = 40% of cost price
Cost price = selling price + loss
⇒ Cost price = 1440 + 40% of cost price
⇒ 60% of cost price = 1440
⇒ Cost price = $\frac{1440}{0.6}$ = INR 2400
Profit

11 Views

Question : What is the value of $\left(k-\frac{1}{k}\right)\left(k^2+\frac{1}{k^2}\right)\left(k^4+\frac{1}{k^4}\right)\left(k^8+\frac{1}{k^8}\right)\left(k^{16}+\frac{1}{k^{16}}\right) ?$

Option 1: $k^{64}-\frac{1}{k^{64}}$

Option 2: $\frac{k^{32}-\frac{1}{k^{32}}}{k-\frac{1}{k}}$

Option 3: $k^{32}-\frac{1}{k^{32}}$

Option 4: $\frac{k^{32}-\frac{1}{k^{32}}}{k+\frac{1}{k}}$

Team Careers360 20th Jan, 2024

Correct Answer: $\frac{k^{32}-\frac{1}{k^{32}}}{k+\frac{1}{k}}$


Solution : Consider, $\left(k-\frac{1}{k}\right)\left(k^2+\frac{1}{k^2}\right)\left(k^4+\frac{1}{k^4}\right)\left(k^8+\frac{1}{k^8}\right)\left(k^{16}+\frac{1}{k^{16}}\right)$
Multiplying and dividing by $(k+\frac{1}{k})$
⇒ $\left(k-\frac{1}{k}\right)\left(k^2+\frac{1}{k^2}\right)\left(k^4+\frac{1}{k^4}\right)\left(k^8+\frac{1}{k^8}\right)\left(k^{16}+\frac{1}{k^{16}}\right)=\frac{(k-\frac{1}{k})(k+\frac{1}{k})(k^2+\frac{1}{k^2})(k^4+\frac{1}{k^4})(k^8+\frac{1}{k^8})(k^{16}+\frac{1}{k^{16}})}{k+\frac{1}{k}}$
Now using, $(a+b)(a-b)=a^2 - b^2$
⇒ $\left(k-\frac{1}{k}\right)\left(k^2+\frac{1}{k^2}\right)\left(k^4+\frac{1}{k^4}\right)\left(k^8+\frac{1}{k^8}\right)\left(k^{16}+\frac{1}{k^{16}}\right)=\frac{(k^2-\frac{1}{k^2})(k^2+\frac{1}{k^2})(k^4+\frac{1}{k^4})(k^8+\frac{1}{k^8})(k^{16}+\frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{(k^4-\frac{1}{k^4})(k^4+\frac{1}{k^4})(k^8+\frac{1}{k^8})(k^{16}+\frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{(k^8-\frac{1}{k^8})(k^8+\frac{1}{k^8})(k^{16} + \frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{(k^{16} - \frac{1}{k^{16}})(k^{16} + \frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{k^{32} - \frac{1}{k^{32}}}{k+\frac{1}{k}}$
Hence, the correct answer is $\frac{k^{32} - \frac{1}{k^{32}}}{k+\frac{1}{k}}$.

10 Views

Question : Mrinalini Vikram Sarabhai, the Bharatanatyam legend, was also recognised for which of the following dance forms?

Option 1: Kathak

Option 2: Kathakali

Option 3: Kuchipudi

Option 4: Odissi

Team Careers360 13th Jan, 2024

Correct Answer: Kathakali


Solution : The correct option is Kathakali.

Mrinalini Vikram Sarabhai was a renowned Indian classical dancer, choreographer, and cultural icon. She made significant contributions to the field of dance and was a pioneer in promoting Indian classical dance forms. She received her training in the classical

46 Views

In how many ways can we get a job into ISRO ?

Aditya kumar 17th Aug, 2022

hlwo aspirant

hope you are doing well

You need to score at least 65% in your BTech/ BE program.

Your age should be below 35 years of age.

You must take the test by the ISRO Centralized Recruitment Board.

The test includes a written test and an interview to join

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