Hello nutan

I'm sure about that you can registerd 2 time or not..

But their is no need and benefit of doing registrations 2 time..

You have  to do  only 1 time registration for neet counselling in Maharashtra 2020..

But you can fill many choices in the form..

Aspirant, I

Hi

Here's a brief regarding JEE mains 2021:-

Your JEE mains 2021 will be conducted in  four sessions i. e

*February session

* March session

*April session.

* May session

NTA has released jee mains 2021 application  form on 16th December 2020 in online mode at official page of jee

Dear aspirant,

Hope you are doing well. As per your query In JEE Main, every student is allowed a total of six attempts in the available years provided . NTA in the official brochure invited applications from students who have cleared class 12 in 2018, 2019 and appearing in 2020.

Hello aspirant

If you wish to cancel admission to a local college and go for a long-term course it's totally fine if you have the confidence that you can score better than JEE 2020. Also as the JEE mains, 2021 is conducted 4 times is in February, March, April, May.

Hello student

Nkp salve Institute of Medical Science Research Centre is a private medical college in Nagpur, Maharashtra. Its fees structure is quite different from the government medical colleges.

The MBBS course fee for the year of 5 years and 6 months is 27,50,000. This amount of rupees is payable

Hello. There would be an issue of network , which is why the pdf didn't load. Still we will check on our side, hope your problem gets solved soon.

Hope that helps!

Hello Aspirant,

There are some technical issues due to which so many people are facing different kinds of problem, upon which MCC is working to resolve this as soon as possible. Now in your case if you did not got the message of successful payment from MCC then it means

T1 = 27 = 300K

Let initial pressure be P1 and final be P2 .

Now, as gas is compressed to 10 times the original pressure then :-

P1/P2 = 1/10

And, gamma = 1.4

And since the gas is compressed, so we will use

(T1 / T2 )^gamma =

Hello there!

Here is the solution regarding your question.

Given,

T = 27°C [which is equal to 300 K].

Work done = 2.303 RT log Vf / Vi  [ for isothermal process ].

W = 2.303 x 8.31 x 300 x log 3/1 [ log 3 = 0.48 ].

W

Hello there!

Here is the solution regarding your question.

Temperature will be constant as the process mentioned is Isothermal.

Now,

PV = nRT

PV = constant

So, PiVi = PfVf       -(1)

Also, at NTP,

P = 1 atm  [1 atm = 10 N/m²]

V = 22.4 litres

T = 273