M.Arch
Hello.
The Jee mains will be conducted only in online mode from this year and you cannot attempt the exam in offline mode.
Hope this helps.
Hi dear,
If you have a good basic then you may go for these books
For physics
1.previous years paper of main and advance
2.40 days jee main by arihant publication.
For chemistry
1.NCERT
2.previous year paper of main and advance
For mathematics
1.coordinate geometry by SL LONEY
2.CALCULUS by
Hi Tania,
M.arch is a great masters digree to pursue after completing you Barch digree. It is a two year course and the eligibility criteria is an aggregate of 50% marks in the qualifying digree.
Top Institutes offering M.Arch. Course are:
Dear Rishabh, M.Arch is a Post Grafuate course. You need to study B.Arch first ti be eligible for M.Arch. NATA is the entrance examination for admission into B.Arch. For being eligible for NATA, you should have completed your 10+2 with a minimum aggregate of 50%. The last date to fill
Hello Hitesh,
Yes, you would be able to change during the correction period.
So what you need to do is go the official website, log in using your details and in the option available to make the changes for the correction, please put the necessary details.
For further details, if
dear aspirant,
no the AIIMS exam dates are fixed it is can't be done before march and it is online exam ,the AIIMS 2019 exam is going to be conducted on may 25 and 26.
check the below link for more information:https://medicine.careers360.com/exams/aiims-mbbs
thank you.
Hello Krishna!
The exam date of jee main is from 6-12 april. It will be conducted in two shifts through online mode. Whereas the exam date of MHT-CET is from2-13 may.
Now,look at these points for preparation
Firstly, focus on basic concepts and formula of physics. Ncert chemistry Is just
Dear Jarshitha, your code will be 01.
Code 1 is for those Candidates those are appearing in Class 12thand their result is awaited in 2019, they are only eligible to get admission in the MBBS or BDS programme if they qualify the examination (10+2) with the required percentage
hii Ansh,
this year the general cutoff of JEE main paper 1 will be approximate 85 percentile or more.
according to the formula, Rank = ( 100-your percentile )* total no. Of students /100,
your rank is 244,851.
At this rank it will be quit difficult to get any Government
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