Staff Selection Commission Combined Graduate Level Exam
Question : Rs. 16,820 is divided between two brothers of age 27 years and 25 years. They invested their money at 5% per annum compound interest in such a way that both will receive equal money at the age of 40 years. The share (in Rs.) of elder brother is:
Option 1: Rs. 8,280
Option 2: Rs. 8,410
Option 3: Rs. 8,820
Option 4: Rs. 8,000
Correct Answer: Rs. 8,820
Solution : Suppose Share of elder brother = Rs. $y$ ∴ Share of younger brother = Rs. $(16820 – y)$ Using the given formula, $A=P(1+\frac{R}{100})^n$ According to the question, $y(1+\frac{5}{100})^{13}=(16820-y)(1+\frac{5}{100})^{15}$ ⇒ $y=(16820-y)(1+\frac{5}{100})^{2}$ ⇒ $y=(16820-y)(\frac{21}{20})^{2}$ ⇒ $y(\frac{20}{21})^{2}=(16820-y)$ ⇒ $\frac{400y}{441}+y=16820$ ⇒ $\frac{400y+441y}{441}=16820$ ⇒ $\frac{881y}{441}=16820$ ⇒ $y = 441×20
Question : A discount of 20% is given for the purchase of two books by a bookseller and a discount of 25% is offered if a customer buys more than two books. A 10% discount is being offered to all the customers on purchase of one book. An additional 5% discount will be given to students. Sohan, a student of M.Com. in college, bought a book for INR 513. What was the marked price of the book?
Option 1: INR 650
Option 2: INR 540
Option 3: INR 600
Option 4: INR 605
Correct Answer: INR 600
Solution : Let's denote the marked price of the book as $x$. For the purchase of one book, a 10% discount is offered. ⇒ The price Sohan paid is 90% of the marked price 90% of $x$ = 0.9$x$ Sohan is a student, so an additional
Question : In triangle ABC, $\angle$ B = 90°, and $\angle$C = 45°. If AC = $2 \sqrt{2}$ cm then the length of BC is:
Option 1: 3 cm
Option 2: 2 cm
Option 3: 1 cm
Option 4: 4 cm
Correct Answer: 2 cm
Solution : AC = $2 \sqrt{2}$ cm Also, $\angle$B = 90°, and $\angle$C = 45° Applying angle sum property in triangle ABC, $\angle$ A + $\angle$ B + $\angle$ C = 180° or, $\angle$A + 90° + 45° = 180° or, $\angle$A = 45° Since, $\angle$A
Question : Directions: Which of the following diagrams represents the relationship between Brother, Husband, and Men?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : Brother and Husband come under the category of men. They cannot be women. So, their circles will lie inside that of men. Also, a brother can be a husband and a husband can be a brother. So, they will have some areas in common in the
Question : Who has the power to prorogue the Lok Sabha?
Option 1: The Speaker
Option 2: The Prime Minister
Option 3: The Minister for Parliamentary Affairs
Option 4: The President
Correct Answer: The President
Solution : The correct answer is The President.
The President has the authority to convoke and prorogue either House of Parliament or dissolve the Lok Sabha. The Lower House is dissolved when five years have passed since the first day of its sessions, by Article 83(2)
Question : Nylon threads are made of
Option 1: Polyester polymer
Option 2: Polyamide polymer
Option 3: Polyvinyl polymer
Option 4: Polysaccharide
Correct Answer: Polyamide polymer
Solution : The correct answer is Polyamide polymer.
Nylon polymers are synthetic polymers derived from polyamide polymers. Polymerization produces Nylon polymers, such as Nylon-6, and forms repeating units known as monomers. Because of their strength and adaptability, These synthetic polymers have many applications in textiles, plastics
Question : The whole surface area of a pyramid whose base is a regular polygon is 340 cm2, the area of its base is 100 cm2, and the area of each lateral face is 30 cm2. Then the number of lateral faces is:
Option 1: 8
Option 2: 9
Option 3: 7
Option 4: 10
Correct Answer: 8
Solution : Given: Whole surface area = 340 cm2 Area of each lateral face = 30 cm2 Area of base = 100 cm2 Whole surface area = lateral surface area + area of the base ⇒ 340 = lateral surface area + 100 $\therefore$
Question : If $\frac{a^{2} - bc}{a^{2}+bc}+\frac{b^{2}-ca}{b^{2}+ca}+\frac{c^{2}-ab}{c^{2}+ab}=1$, then the value of $\frac{a^{2}}{a^{2}+bc}+\frac{b^{2}}{b^{2}+ac}+\frac{c^{2}}{c^{2}+ab}$ is:
Option 1: 0
Option 2: 1
Option 3: –1
Option 4: 2
Correct Answer: 2
Solution : $\frac{a^{2}-bc}{a^{2}+bc}+\frac{b^{2}-ca}{b^{2}+ca}+\frac{c^{2}-ab}{c^{2}+ab}=1$ Adding 3 on both sides, $⇒(\frac{a^{2}-bc}{a^{2}+bc}+1)+(\frac{b^{2}-ca}{b^{2}+ca}+1)+(\frac{c^{2}-ab}{c^{2}+ab}+1)=1+3$ $⇒(\frac{a^{2}-bc+a^{2}+bc}{a^{2}+bc})+(\frac{b^{2}-ca+b^{2}+ca}{b^{2}+ca})+(\frac{c^{2}-ab+c^{2}+ab}{c^{2}+ab})=4$ $⇒(\frac{2a^{2}}{a^{2}+bc})+(\frac{2b^{2}}{b^{2}+ca})+(\frac{2c^{2}}{c^{2}+ab})=4$ $⇒\frac{a^{2}}{a^{2}+bc}+\frac{b^{2}}{b^{2}+ac}+\frac{c^{2}}{c^{2}+ab}=2$ Hence, the correct answer is 2.
Question : If $x^2-7 x+1=0$ and $0<x<1$, what is the value of $x^2-\frac{1}{x^2}?$
Option 1: $21\sqrt{5}$
Option 2: $-21\sqrt{5}$
Option 3: $28\sqrt{5}$
Option 4: $-28\sqrt{5}$
Correct Answer: $-21\sqrt{5}$
Solution : Given: $x^2-7 x+1=0$ ⇒ $x+\frac{1}{x}=7$ Squaring the equation, we get, $(x+\frac{1}{x})^2=7^2$ ⇒ $x^2+\frac{1}{x^2}+2=49$ ⇒ $x^2+\frac{1}{x^2}=47$ And we know, $(x-\frac{1}{x})^2=x^2+\frac{1}{x^2}-2$ ⇒ $(x-\frac{1}{x})^2=47-2=45$ ⇒ $x-\frac{1}{x}=\pm\sqrt{45}$ ⇒ $x=-\sqrt{45}$ [As $0<x<1$] Now consider, $x^2-\frac{1}{x^2}$ Using $a^2-b^2=(a-b)(a+b)$ $=(x+\frac{1}{x})(x-\frac{1}{x})$ $=7\times (-\sqrt{45})$ $=-7\times 3\sqrt5=-21\sqrt5$ Hence, the correct answer is $-21\sqrt5$.
Question : Directions: Three statements are given, followed by four conclusions numbered I, II, III, and IV. Assuming the statements to be true, even if they seem to be at variance with commonly known facts, decide which of the conclusions logically follow(s) from the statements. Statements: Some desks are trays. Some trays are plates. Some plates are desks. Conclusions: I. All desks are plates. II. All plates are desks. III. Some plates are trays. IV. All trays are desks.
Option 1: Only conclusion III follows
Option 2: Only conclusion IV follows
Option 3: Only conclusion II follows
Option 4: Only conclusion I follows
Correct Answer: Only conclusion III follows
Solution : The possible Venn diagram according to the given statements is as follows –
Let's analyse the conclusions – Conclusion I: All desks are plates – From the above diagram, it is clear that only some parts of the circle that are desks
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