a body of mass 60 kg is inside a lift of masses 940 kg and presses the button on control panel the lift start moving upwards with an acceleration 1.5 metre per second square if g is equals to 10 metre per second inverse -2 to the tension in the supporting cable is
Answer (1)
9th Dec, 2019
Let the mass of the lift is M
And the mass of the body be m
Now a be the acceleration of the lift
And g be the gravitational acceleration.
Now we have to find the tension .
Let the tension be T.
Hence T-(m+M)g=(m+M)a
T=(m+M)(g+a).
Now in the question we are given that
M=940
m=60
g=10
a=1.5
Hence T=1000*11.5=11500N
And the mass of the body be m
Now a be the acceleration of the lift
And g be the gravitational acceleration.
Now we have to find the tension .
Let the tension be T.
Hence T-(m+M)g=(m+M)a
T=(m+M)(g+a).
Now in the question we are given that
M=940
m=60
g=10
a=1.5
Hence T=1000*11.5=11500N
Comments (0)
Related Questions
Trending Articles/News
