a body travels to 200 centimetre in first 2s 220 CM in next 4 second with deceleration the velocity of the body at end of the 7th second is answer is 10 cm per second
Answer (1)
23rd Aug, 2020
Hello,
The displacement of a body is given by s = ut + 1/2 * a * t^2
Case 1: When body covers 200 cm in 2s
s = ut + 1/2 * a * t^2
200 = u * 2 + 1/2 * a * 2^2
u + a = 100 (Equation 1)
Case 2: When body covers 220 cm in next 4s, therefore in total it will cover (200+220 = 420 cm) in (2+4 = 6 sec)
s = ut + 1/2 * a * t^2
420 = u*6 + 1/2 * a * 6^2
u + 3a = 70 (Equation 2)
Solving Equation 1 and Equation 2, we get:
u = 115 cm/s and a = -15 cm/s^2
Now, v = u + at
At the end of 7 seconds, t = 7, Substituting the values in above equation, we get:
v = 115 - 15 * 7
v = 10 cm/sec (Answer)
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