Question : A right circular cylinder of the maximum possible size is cut out from a solid wooden cube. The remaining material of the cube is what percentage of the original cube? (Take $\pi=3.14$)
Option 1: 22.4
Option 2: 21.5
Option 3: 22.8
Option 4: 21.8
Correct Answer: 21.5
Solution :
Let the dimensions of the wooden cube = $a \times a \times a$
The volume of the wooden cube = $a^3$
The diameter of the cylinder and its height = $a$
The volume of the cylinder = $\pi r ^2 h$, where $r$ and $h$ are the radius and height of the cylinder.
= $\pi \times (\frac{a}{2})^2 \times a$
= $\frac{\pi \times a^3}{4}$
= $\frac{3.14 \times a^3}{4}$
= $0.785 \times a^3$
Thus, remaining material $=a^3-0.785a^3 = 0.215 \times a^3$
Percentage of the remaining material = $\frac{0.215 \times a^3}{a^3} \times 100$ = 21.5%
Hence, the correct answer is 21.5.
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