Question : Directions: After 6 years, the sum of the years of service of P, Q, and R will be 56 years. Before 3 years, the sum of years of service of Q and R was 17 years. What is the current length of service of P?
Option 1: 17 years
Option 2: 15 years
Option 3: 11 years
Option 4: 12 years
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Correct Answer: 15 years
Solution : Let, the length of years of service of P = P years The length of years of service of Q = Q years The length of years of service of R = R years ⇒After 6 years, the sum of the years of service of P, Q, and R = (P + 6) + (Q + 6) + (R + 6) = 56 P + Q + R + 18 = 56 P + Q + R = 38 ----- (I) ⇒Before 3 years, the sum of years of service of Q and R = (Q – 3) + (R – 3) = 17 R + Q – 6 = 17 R + Q = 23 ----- (II) From the equation (I) and (II) above, P + 23 = 38 P = 15 years
Therefore, the current length of service of P is 15 years. Hence, the second option is correct.
Application | Eligibility | Dates | Syllabus
Question : Directions: If P means +, Q means –, R means ÷, and S means ×, then which of the following equations is correct?
Option 1: 14 R 7 S 6 P 4 Q 3 = 11
Option 2: 9 S 8 P 6 R 4 S 8 = 80
Option 3: 3 S 6 P 2 Q 3 R 6 = 17.5
Option 4: 11 R 12 S 48 P 10 Q 6 = 48
Question : Directions: P is 4 years older than Q. Q is 7 years younger than R. R is 5 years older than S. S is 8 years younger than T. Who is the youngest?
Option 1: P
Option 2: Q
Option 3: R
Option 4: S
Question : Directions: If P means +, Q means –, R means ÷, and S means ×, then, 46 S 14 R 2 P 11 Q 6 = ?
Option 1: 319
Option 2: 327
Option 3: –217
Option 4: 317
Question : Directions: Which two numbers from amongst the given options should be interchanged to make the given equation correct? (63 ÷ 9 + 17) ÷ 11 = 15 – 195 ÷ 17 – 2
Option 1: 11 and 15
Option 2: 17 and 15
Option 3: 195 and 63
Option 4: 2 and 15
Question : Directions: The present age of P is 45 years. 9 years hence, the ages of P and Q will be in the ratio 6 : 7. What is the present age (in years) of Q?
Option 1: 64
Option 2: 54
Option 3: 63
Option 4: 53
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