Question : If $a \cot \theta+b \operatorname{cosec} \theta=p$ and $b \cot \theta+a \operatorname{cosec} \theta=q$, then $p^2-q^2$ is equal to ____.
Option 1: $b^2-a^2$
Option 2: $a^2-b^2$
Option 3: $b-a$
Option 4: $a^2+b^2$
New: SSC CGL 2025 Tier-1 Result
Latest: SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: $b^2-a^2$
Solution :
$a \cot \theta+b \operatorname{cosec} \theta=p$
$b \cot \theta+a \operatorname{cosec} \theta=q$
So, $p^2-q^2$
= $(a \cot \theta+b \operatorname{cosec} \theta)^2 - (b \cot \theta+a \operatorname{cosec} \theta)^2$
= $a^2 \cot^2 \theta+b^2 \operatorname{cosec}^2 \theta + 2×a \cot \theta×b \operatorname{cosec} \theta$ – $(b^2 \cot^2 \theta+a^2 \operatorname{cosec}^2\theta+2×b \cot \theta×a \operatorname{cosec} \theta)$
= $a^2 \cot^2 \theta+b^2 \operatorname{cosec}^2 \theta + 2×a \cot \theta×b \operatorname{cosec} \theta$ – $b^2 \cot^2 \theta–a^2 \operatorname{cosec}^2\theta - 2×b \cot \theta×a \operatorname{cosec} \theta$
= $a^2 \cot^2 \theta-a^2 \operatorname{cosec}^2\theta+b^2 \operatorname{cosec}^2 \theta - b^2 \cot^2 \theta$
= $a^2 (\cot^2 \theta-\operatorname{cosec}^2\theta)+b^2( \operatorname{cosec}^2 \theta - \cot^2 \theta)$
= $b^2-a^2$
Hence, the correct answer is $b^2-a^2$.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates BrochureYour Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.




