Question : If $b \sin \theta=a$, then $\sec \theta+\tan \theta=?$

Option 1: $\sqrt{\frac{b+a}{b-a}}$

Option 2: $\sqrt{\frac{1}{b+a}}$

Option 3: $\sqrt{\frac{1}{b-a}}$

Option 4: $\sqrt{\frac{b-a}{b+a}}$

Question : Find the value of: $\sqrt{\frac{1 - \sin 3 \theta}{1 + \sin 3 \theta}}$

Option 1: $\sec 3 \theta - \tan 3 \theta$

Option 2: $(\sec 3 \theta - \tan 3 \theta)^3$

Option 3: $(\sec 3 \theta - \tan 3 \theta)^2$

Option 4: $\sec 3 \theta + \tan 3 \theta$

Question : If $\frac{\sin ^2 \theta}{\cos ^2 \theta-3 \cos \theta+2}=1, \theta$ lies in the first quadrant, then the value of $\frac{\tan ^2 \frac{\theta}{2}+\sin ^2 \frac{\theta}{2}}{\tan \theta+\sin \theta}$ is:

Option 1: $\frac{2 \sqrt{3}}{27}$

Option 2: $\frac{5 \sqrt{3}}{27}$

Option 3: $\frac{2 \sqrt{3}}{9}$

Option 4: $\frac{7 \sqrt{3}}{54}$

Question : Which of the following is equal to $[\frac{\tan \theta+\sec \theta–1}{\tan \theta–\sec \theta+1}]$?

Option 1: $\frac{1+\sin \theta}{\cos \theta}$

Option 2: $\frac{1+\tan \theta}{\cot \theta}$

Option 3: $\frac{1+\cot \theta}{\tan \theta}$

Option 4: $\frac{1+\cos \theta}{\sin \theta}$

Question : If $2 \cot \theta = 3$, find the value of $\frac{\sqrt{13} \sin \theta – 3 \tan \theta}{3 \tan \theta + \sqrt{13} \cos \theta}$

Option 1: $\frac{1}{\sqrt{13}}$

Option 2: $\frac{2}{\sqrt{13}}$

Option 3: 0

Option 4: $\frac{2}{3}$

Question : If $\sqrt{3} \tan \theta=3 \sin \theta$, then what is the value of $\sin ^2 \theta-\cos ^2 \theta$?

Option 1: $\frac{1}{5}$

Option 2: $\frac{1}{4}$

Option 3: $\frac{1}{2}$

Option 4: $\frac{1}{3}$