Question : In the given figure, B and C are the centres of the two circles. ADE is the common tangent to the two circles. If the ratio of the radii of both circles is 3 : 5 and AC is 40 cm, then what is the value (in cm) of DE?
Option 1: $3\sqrt{15}$
Option 2: $5\sqrt{15}$
Option 3: $6\sqrt{15}$
Option 4: $4\sqrt{15}$
New: SSC CGL 2025 Tier-1 Result
Latest: SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: $4\sqrt{15}$
Solution :
Construct: Draw a line from B to D and C to E.
Given that the ratio of the radius of both the circles is 3 : 5 and AC = 40.
Let $DB = 3x$ and $EC = 5x$.
In $\triangle ABD$ and $\triangle ACE$
$\angle A=\angle A$ (common angle)
$\angle D=\angle E$ (Each angle is $90^{\circ}$)
So, $\triangle ABD\sim\triangle ACE$
$AB:AC = 3:5$
$AB: BC = 3:2$
⇒ $BC=\frac{2}{5}×40=16$
⇒ $BC=16$
⇒ $3x+5x=16$
⇒ $x=2$
⇒ $BD=3x=6$ and $EC=5x=10$
In $\triangle AEC$,
$AE^2=AC^2-EC^2$
⇒ $AE^2=1600-100=1500$
⇒ $AE=10\sqrt{15}$
⇒ $AD: DE=3:2$
⇒ $DE=\frac{2}{5}×10\sqrt{15}=4\sqrt{15}$ cm
Hence, the correct answer is $4\sqrt{15}$.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates BrochureYour Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.




