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Question : The average of n numbers is 42. If 75% of the numbers are increased by 4 each and the remaining numbers are decreased by 8 each, then what is the average of the numbers, so obtained?

Option 1: 44

Option 2: 42.5

Option 3: 43

Option 4: 43.8


Team Careers360 3rd Jan, 2024
Answer (1)
Team Careers360 9th Jan, 2024

Correct Answer: 43


Solution : The average of n numbers is 42, so the total sum of these numbers is 42n.
If 75% of the numbers are increased by 4 each.
The total increase in the sum of these numbers = 0.75n × 4 = 3n
The remaining 25% of the numbers are decreased by 8 each.
The total decrease in the sum of these numbers = 0.25n × 8 = 2n
The new sum of the numbers = 42n + 3n – 2n = 43n
Since the number of elements 'n' hasn't changed, the new average = $\frac{43n }{ n}$ = 43
Hence, the correct answer is 43.

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