Question : The value of $\frac{(0.321)^3+(0.456)^3-(0.777)^3}{0.9 \times(0.107)(0.76)(0.777)}$ is:
Option 1: 60
Option 2: –6
Option 3: –3
Option 4: 30
Correct Answer: –6
Solution :
As we know,
If $a + b + c = 0$
Then, $a^3 + b^3 + c^3 = 3abc$
Now, 0.321 + 0.456 – 0.777 = 0
Then, $0.321^3 + 0.456^3 - 0.777^3 = -3 \times 0.321 \times 0.456 \times 0.777$
So, $\frac{(0.321)^3+(0.456)^3-(0.777)^3}{0.9 \times(0.107)(0.76)(0.777)}$
= $\frac{-3 \times 0.321 \times 0.456 \times 0.777}{0.9 \times 0.107 \times 0.76 \times 0.777}$
= –6
Hence, the correct answer is –6.
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