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Staff Selection Commission Combined Graduate Level Exam

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Question : Who among the following became the first Indian to be invited to perform at the prestigious Lincoln Centre Hall in the United States of America?

Option 1: M. S. Subbulakshmi

Option 2: Zakir Hussain

Option 3: Ravi Shankar

Option 4: Bismillah Khan

Team Careers360 25th Jan, 2024

Correct Answer: Bismillah Khan


Solution : The correct option is Bismillah Khan.

Bismillah Khan, the famous Indian shehnai maestro, was the first Indian to be asked to perform at New York's prestigious Lincoln Centre Hall in 1968. He also received several honours, including the Padma Vibhushan and the Bharat Ratna.

21 Views

Question : In $\triangle ABC$, D and E are points on the sides AB and AC, respectively, such that DE || BC and DE : BC = 6 : 7. (Area of $\triangle {ADE}$ ) : (Area of trapezium BCED) = ?

Option 1: 49 : 13

Option 2: 13 : 36

Option 3: 13 : 49

Option 4: 36 : 13

Team Careers360 25th Jan, 2024

Correct Answer: 36 : 13


Solution :
DE : BC = 6 : 7
Theorem Used:
The ratios of the areas of two similar triangles are equal to the square of the ratio of their corresponding sides
Calculation:
Considering $\triangle$ABC and $\triangle$ADE
$\angle$A = $\angle$A (Common)
As DE || BC

12 Views

Question : The ‘Sorrow of Bengal’ is _______.

Option 1: The Narmada

Option 2: The Damodar

Option 3: The Koshi

Option 4: The Tapi

Team Careers360 25th Jan, 2024

Correct Answer: The Damodar


Solution : The correct answer is The Damodar.

The devastating floods that the River Damodar causes in the West Bengal plains have earned it the nickname "Bengal's sorrow." Because of the southwest monsoon, the Damodar River catchment area receives seasonal rains every year. Depending on the

14 Views

Question : What is the altitude of an equilateral triangle whose side is 15 cm?

Option 1: $15\sqrt3\text{ cm}$

Option 2: $10\sqrt 3\text{ cm}$

Option 3: $\frac{9\sqrt 3 }{2}\text{ cm}$

Option 4: $\frac{15\sqrt 3}{2}\text{ cm}$

Team Careers360 25th Jan, 2024

Correct Answer: $\frac{15\sqrt 3}{2}\text{ cm}$


Solution : Given: The side of the triangle is 15 cm.
Let the altitude be $x$ cm.
The length of the altitude of an equilateral triangle = $\frac{\sqrt3}{2}$ × side of the triangle.
⇒ $x = \frac{\sqrt3}{2}\times15$
⇒ $x = \frac{15\sqrt3}{2}$
Hence, the correct answer

22 Views

Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No error".

One (1) / should keep (2) / his word. (3) / No error (4)

Option 1: (1)

Option 2: (2)

Option 3: (3)

Option 4: (4)

Team Careers360 25th Jan, 2024

Correct Answer: (3)


Solution : The error lies in the third part of the sentence.

When a sentence uses the indefinite pronoun one, it should continue using the same pronoun or its supplementary forms i.e., one's in this case, as it is not correct to use other pronouns

11 Views

Question : What is the sum of the first 9 terms of an arithmetic progression, if the first term is 7 and the last term is 55?

Option 1: 219

Option 2: 137

Option 3: 231

Option 4: 279

Team Careers360 25th Jan, 2024

Correct Answer: 279


Solution : Given: The first term is 7 and the last term is 55.
Using the formula, S9 = $\frac{n}{2}(a+l)$
Where $a$ is the first term, $l$ is the last term of the A.P., and n is the number of terms.
By putting the value of

15 Views

Question : In a cut motion, when the amount of demand is reduced by Rs.100 it is known as

Option 1: Disapproval of policy cut

Option 2: Economy cut

Option 3: Vote on account

Option 4: Token cut

Team Careers360 25th Jan, 2024

Correct Answer: Token cut


Solution : The correct answer is Token cut.

Cut motions are the method of accountability with the opposition in Lok Sabha. It is a form of checks and balances in the Indian constitutional setup. In a token-cut-specific issue. It asks for a discussion on a

15 Views

Question : What is the value of $\left[\frac{12}{(\sqrt5+\sqrt3)}+\frac{18}{(\sqrt{5}-\sqrt3)}\right]$?

Option 1: $15(\sqrt5–\sqrt3)$

Option 2: $3(5\sqrt5+\sqrt3)$

Option 3: $15(\sqrt5+\sqrt3)$

Option 4: $3(3\sqrt5+\sqrt3)$

Team Careers360 25th Jan, 2024

Correct Answer: $3(5\sqrt5+\sqrt3)$


Solution : Given:
$\left[\frac{12}{(\sqrt5+\sqrt3)}+\frac{18}{(\sqrt{5}-\sqrt3)}\right]$
= $\frac{12\sqrt5-12\sqrt 3+18\sqrt5+18\sqrt 3}{(\sqrt5+\sqrt3)(\sqrt{5}-\sqrt3)}$
= $\frac{30\sqrt5+6\sqrt3}{5-3}$
= $\frac{6(5\sqrt5+\sqrt3)}{2}$
= $3(5\sqrt5+\sqrt3)$
Hence, the correct answer is $3(5\sqrt5+\sqrt3)$.

13 Views

Question : If $x+y+z=1, \frac{1}{x}+\frac{1}{y}+\frac{1}{z}=1,$ and $xyz=-1$, then $x^3+y^3+z^3 $ is equal to:

Option 1: –1

Option 2: 1

Option 3: –2

Option 4: 2

Team Careers360 25th Jan, 2024

Correct Answer: 1


Solution : Given:
$x+y+z=1,\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=1$, $xyz=-1$
Consider, $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=1$
⇒ $xy+yz+zx=xyz=-1$
Now, $x+y+z=1$
⇒ $(x+y+z)^2=1^2$
⇒ $x^2+y^2+z^2+2(xy+yz+zx)=1$
⇒ $x^2+y^2+z^2+2(-1)=1$
⇒ $x^2+y^2+z^2=3$
We know, $x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx)$
So, putting all the values, we get,
⇒ $x^3+y^3+z^3-3×(-1)=1×[3-(-1)]$
⇒ $x^3+y^3+z^3=4-3$
$\therefore x^3+y^3+z^3=1$
Hence, the correct answer is 1.

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