Question : If $AD, BE$ and $CF$ are medians of $\triangle ABC$, then which of the following statement is correct?

Option 1: $(AD + BE + CF) > (AB + BC + CA)$

Option 2: $(AD + BE + CF) < (AB + BC + CA)$

Option 3: $(AD + BE + CF ) =  (AB + BC + CA)$

Option 4: $(AD + BE + CF ) = \sqrt2(AB+BC+CA)$

Question : The hypotenuse of a right-angled triangle is 39 cm and the difference of the other two sides is 21 cm. Then, the area of the triangle is:

Option 1: 270 cm²

Option 2: 450 cm²

Option 3: 540 cm²

Option 4: 180 cm²

Question : The sides of a triangle are 20 cm, 21 cm, and 29 cm. The area of the triangle formed by joining the midpoints of the sides of the triangle will be:

Option 1: $67 \frac{2}{3}$ cm²

Option 2: $52 \frac{1}{2}$ cm²

Option 3: $47 \frac{1}{2}$ cm²

Option 4: $58 \frac{1}{3}$ cm²

Question : If in triangle ABC, MN is parallel to BC, and M and N are points on AB and AC respectively. The area of quadrilateral MBCN = 130 cm². If AN : NC = 4 : 5, then the area of triangle MAN is:

Option 1: 40 cm²

Option 2: 65 cm²

Option 3: 32 cm²

Option 4: 45 cm²

Question : What is the area of a rhombus whose diagonals are 8 cm and 13 cm?

Option 1: 52 cm²

Option 2: 96 cm²

Option 3: 44 cm²

Option 4: 84 cm²