Engineering
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Question : If $\tan \theta=\frac{8}{15}$, then the value of $\sqrt{\frac{1-\sin \theta}{1+\sin \theta}}$ is:
Option 1: $\frac{1}{5}$
Option 2: $\frac{3}{5}$
Option 3: $\frac{2}{5}$
Option 4: $\frac{4}{5}$
Correct Answer: $\frac{3}{5}$
Solution : $\tan \theta=\frac{8}{15}=\frac{\text{Perpendicular}}{\text{Base}}$ $\therefore$ Hypotenuse = $\sqrt{8^2+15^2}=\sqrt{289}= 17$ So, $\sin \theta=\frac{8}{17}$ $\sqrt{\frac{1-\sin \theta}{1+\sin \theta}}=\sqrt{\frac{1-\frac{8}{17}}{1+\frac{8}{17}}}=\sqrt{\frac{\frac{9}{17}}{\frac{25}{17}}}=\sqrt{\frac{9}{25}}=\frac{3}{5}$ Hence, the correct answer is $\frac{3}{5}$.
Engineering is one of the top fields with wide scope and vast number of opportunities. Engineering colleges in Bangalore are given below:
1) IIIT Bangalore
2) Ramaiah Institute of Technology
3) JAIN (Deemed-to-be-university), Faculty of Engineering and Technology
4) Dayananda Sagar College of Engineering
5) MVJ College of Engineering
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