All Questions

NTA

Follow
Showing 51 - 60 out of 1376 Questions
12 Views

i passed 12th in 2022 but due to less than 50% in pcb I reappeared class 12 in 2023 from same school but now my Marksheet mentions private candidate, according to new notice by nta posted on 9th Feb 2024 , private candidates are not eligible for neet ,what should I do now?

Ishita 21st Aug, 2024

Hello Aspirant

You may have read the notice wrong because in the NEP 2020, it is nowhere mentioned that private candidates cannot appear for NEET.

The eligibility criteria for NEET is that the candidate must have passed Class 10 or equivalent with at least 60% aggregate marks and be appearing

25 Views

neet ug syllabus updated 2024 from nta

Sajal Trivedi 28th Jan, 2024

Hello aspirant,

The NMC syllabus for NEET 2024 has been made available at nta.ac.in by the National Testing Agency (NTA). Three courses are covered in the NEET 2024 syllabus: biology, chemistry, and physics. Botany and Zoology are the two additional divisions of NEET 2024 Biology. The NEET syllabus for 2024

142 Views

Hello all, I am Unable to login on jee main nta online website. Ive entered correct password and application no. but when entering security pin the website shows that pin is incorrect despite of adding correct pins more than 30 times. Please help on this as login is important. Thankyou in advance.

Devyani Prakash 21st Feb, 2024

Hello student,

You could try the following:

1. Try logging in from a different device

2. Refresh the website and re-try logging in

3. Check your network and connectivity

4. Maybe the pin is incorrect- there could be a discrepancy in some digit, or there's some issue with case sensitivity,

10 Views

Question : The ratio of the total surface area and volume of a sphere is 2 : 7. Its radius is:

Option 1: 7.5 cm

Option 2: 10.5 cm

Option 3: 10 cm

Option 4: 7 cm

Team Careers360 20th Jan, 2024

Correct Answer: 10.5 cm


Solution : Let the radius of the sphere be $r$.
Total surface area of the sphere = $4 \pi r^2$
Volume of the sphere = $\frac{4}{3} \pi r^3$
According to the question,
$4 \pi r^2 : \frac{4}{3} \pi r^3 = 2 : 7$
⇒ $\frac{3}{r} =

The question have been saved in answer later, you can access it from your profile anytime. Access now