NTA
Hello Student , NTA has already published JEE Main session 1 result . Your NTA score which is 72.9999 is the percentile that you got in session 1. Considering you as a general category candidate your expected rank would be around 276211 - 310501. If you need more information regarding
Hello student
Your NTA score is your percentile. So that means your percentile is also 43.92.
Your rank will release alongwith the final JEE Main 2024 result after the April session result. As per trends, your rank can fall between 573698 - 644920.
Based on this percentile, it will be
Hello student,
The NTA score is the same as percentile. Your rank will release with the final result after the April session result. As per trends, your rank could tentatively fall between 573698 - 644920.
If you want to check your rank range based on your percentile, then you can
If you want to predict your rank range based on your NTA score/percentile, then you can refer to the Careers360 JEE Main Rank Predictor: https://engineering.careers360.com/jee-main-rank-predictor?
Your rank will be released with the final result when the April session result is out. However, tentative rank will fall between 84500 - 94990 as per trends.
Talking about the scope of admission based on this percentile, then you have chances in some colleges like Ghani Khan
Based on your percentile, it will be difficult to get colleges like NITs and IIITs or any college through JoSAA Counselling for that matte. I suggest that you appear for the second attempt to improve your score and get chances of admission into better colleges.
If you want
I had the same issue and I had called the NTA and they said that in the box where you fill school/college name and address, just put only the name of school/college. I tried that and I was able to submit mine today.
Hello Aspirant
You may have read the notice wrong because in the NEP 2020, it is nowhere mentioned that private candidates cannot appear for NEET.
The eligibility criteria for NEET is that the candidate must have passed Class 10 or equivalent with at least 60% aggregate marks and be appearing
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