Dear aspirant, you can easily get CSE in JIIT Noida, Sector 128 branch. It is difficult to get IT with 86-88 percentage.

College administration never told how many seats are under board admission or JEE admission but maximum seats are filled in Noida campus(both 62 and 128) with JEE mains score.

Hello goursiddhant

I hope you are doing good. I would like to know you that

accelaration is actually changing of velocity per sec

intitalc velocity =0 m/s (as start from rest)

final velocity=75m/s

change in velocity=75-0=75m/s

hence required acceleration will be

=75/15=5 m/(s^2)

If you have any other doubt then you can always reach us to clear them :)

Hello,

If you get seat in the second counselling then the seat you got in the first counselling will get cancelled not the seat you got in second counselling. If you did not get seat in the second counselling then you will have the seat that you got in the first counselling only if you have submitted the joining report and all the original documents in the college that you have got in the first counselling that is if you have reported your self in the college that you got in the first counselling. If you do not report then even if you did not get college in the second counselling you will still loose that college that you got in the first counselling.

Hello aspirant,

Although you have given the details in the query but what exactly you wanted to ask that you have not mentioned in the query. the student experts are unable to answer you with a proper solution to your query. Please write up some necessary details in the question so that we can be able to answer you.

If you have any sort of doubt, feel free to ask us in the comment section.

Hope, this helps you.

Hello there,

Let we take angle Thita as 'x' . We have to prove that Sinx - Cosx +1 / Sinx + Cosx - 1 = 1/ Secx - Tanx

So now we will take the LHS of the question.

Now multiply the numerator and denominator by Sinx + Cosx +1

Now, our left side becames 1+ Sinx / Cosx

Now again multiply the numerator and denominator by 1- Sinx

So we get , Cosx / 1 - Sinx.

Now just divide the numerator and denominator by Cosx .

Hence We get 1/ Secx - Tanx

Hope it helps you.

Hello aspirant!

Your query does not make sense to me. Please add more information to the query so that we can help you with your queries.

Hi Candidate,

The time needed to throw the stone upwards and downwards in the entire journey is equal to 9 seconds. For upwards, V1 =u+10(t1), So V1= 10t1, and for Downwards journey- V2= V1 +10t2.

Now if we put the value of V1 with V2 we get- V2= u+10t1+10t2, where the value of t1+t2= 9 seconds, and u (initial)= 0. So the value of V2= 10*9=90 metres per second.

Hope that this answer helps you. Have a Good Day!!

Hello,

I am sorry to inform you but there are no private colleges in Panchkula. There is only one GOVENMENT POST GRADUATION COLLEGE in Panchkula.

However there are various private colleges offering the same course throughout Haryana. I would list them for your help:

1. Dyal Singh College, Karnal
2. K.L. Mehta Dayanand College For Women, Faridabad
3. GDC Memorial College, Bhiwani
4. Maharishi Dayanand University, Rohtak
5. G.D. Goenka, Gurgaon

Hope it helps

Good luck