Saveetha Engineering College, Chennai
Hello dear aspirant
Given that: Thickness = 0.002 m & Velocity = 5750 m/s
We know that: Velocity = Frequency × Length
5750 = f × 0.0002
f = 5750 / 0.002
f = 2.875 × 10^6 Hz
Therefore, the fundamental frequency of the sound wave in the crystal is
Let me put some data in front of you about these two colleges.
Comparative Insights VIT Vellore JIIT Noida
Average CSE Package (2019-20) 9.1 LPA 7 LPA
Course Fees 7.80 Lakhs 8.90 Lakhs
Campus Size 372 acres 16 acres
NIRF Ranking(2020) 15 115
Students overall rating 4.3/5 3.8/5
(Info Source:
Dear aspirant, you can easily get CSE in JIIT Noida, Sector 128 branch. It is difficult to get IT with 86-88 percentage.
College administration never told how many seats are under board admission or JEE admission but maximum seats are filled in Noida campus(both 62 and 128) with JEE mains
Hello goursiddhant
I hope you are doing good. I would like to know you that
accelaration is actually changing of velocity per sec
intitalc velocity =0 m/s (as start from rest)
final velocity=75m/s
change in velocity=75-0=75m/s
hence required acceleration will be
=75/15=5 m/(s^2)
If you have any other doubt then
Hello,
If you get seat in the second counselling then the seat you got in the first counselling will get cancelled not the seat you got in second counselling. If you did not get seat in the second counselling then you will have the seat that you got in the
Hello aspirant,
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