Saveetha Engineering College, Chennai
Hello goursiddhant
I hope you are doing good. I would like to know you that
accelaration is actually changing of velocity per sec
intitalc velocity =0 m/s (as start from rest)
final velocity=75m/s
change in velocity=75-0=75m/s
hence required acceleration will be
=75/15=5 m/(s^2)
If you have any other doubt then
Hello,
If you get seat in the second counselling then the seat you got in the first counselling will get cancelled not the seat you got in second counselling. If you did not get seat in the second counselling then you will have the seat that you got in the
Hello aspirant,
Although you have given the details in the query but what exactly you wanted to ask that you have not mentioned in the query. the student experts are unable to answer you with a proper solution to your query. Please write up some necessary details in the question
You must produce a caste certificate as and when asked for it. It can be used for reservation in educational institutes, jobs, etc. The problem is that when you apply for a central government job, you have to produce your OBC caste certificate which has been issued by the state
Hello there,
Let we take angle Thita as 'x' . We have to prove that Sinx - Cosx +1 / Sinx + Cosx - 1 = 1/ Secx - Tanx
So now we will take the LHS of the question.
Now multiply the numerator and denominator by Sinx + Cosx
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Hi Candidate,
The time needed to throw the stone upwards and downwards in the entire journey is equal to 9 seconds. For upwards, V1 =u+10(t1), So V1= 10t1, and for Downwards journey- V2= V1 +10t2.
Now if we put the value of V1 with V2 we get- V2= u+10t1+10t2, where
I am sorry to inform you but there are no private colleges in Panchkula. There is only one GOVENMENT POST GRADUATION COLLEGE in Panchkula.
However there are various private colleges offering the same course throughout Haryana. I would list them for your help:
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