10 litres of ethyline glycol contain 310 g of ethyline glycol .The active mass of ethyline glycol will be
Answer (1)
15th Dec, 2020
Dear student,
Active mass is defined as number of gram mole per litre. Or in another words molar concentration.
Active mass of any substance "A" is given as :-
[A] = mass of A (in gram) / molar mass of A (in g/mol) × Volume of solution ( in litre ).
So, according to question :-
A = ethylene glycol
V = 10 L
Mass of A ( in gram ) = 310
Molar mass of A = 62.07 g/mol
Therefore active mass of ethylene glycol is :-
310 / (62.07 × 10) = 0.499 mol / litre.
Or approximately - 0.5 mol / litre
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