Question : 6 labourers can finish a work in 16 days. 10 labourers are available, but the work is to be finished in 8 days. How many more labourers are to be called to finish the work in time?
Option 1: 2
Option 2: 0
Option 3: 4
Option 4: 1
Correct Answer: 2
Solution :
Given: 6 labourers can finish a task in 16 days.
10 labourers are available, but the work is to be finished in 8 days.
Let the number of labourers added be $x$.
$\frac{M_{1}\times D_{1}}{W_{1}}=\frac{M_{2}\times D_{2}}{W_{2}}$, Where $M_1$ and $M_2$ are labourers, $D_1$ and $D_2$ are days and $W_1$, and $W_2$ are work done.
Substituting the values in the above formula, we get,
$⇒\frac{6 × 16}{1}$ = $\frac{(10 + x) × 8}{1}$
$⇒96 = 80 + 8x$
$⇒x = 2$
Hence, the correct answer is $2$.
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