Question : A rectangular lawn whose length is twice its breadth is extended by having four semi-circular portions on its sides. What is the total area (in ${m}^2$ ) of the lawn if the smaller side of the rectangle is 12 m? (Take $\pi=3.14$ )
Option 1: 853.2
Option 2: 308.64
Option 3: 444
Option 4: 548.32
Correct Answer: 853.2
Solution :
Given: Breadth = 12
Length = 2 × Breadth
= 2 × 12
= 24 m
Area of rectangle = Length × Breadth
= 12 × 24
= 288 m
2
Area of semi-circle on larger side = $\frac{1}{2}× \pi ×12^2$
= $72\pi\ m^2$
Area of semi-circle on smaller side = $\frac{1}{2} ×\pi × 6^2$
= $18\pi\; m^2$
The total area of the lawn = Area of rectangle + 2 × Area of the semi-circle on the larger side + 2 × Area of the semi-circle on the smaller side
= $288 + (2 × 72\pi) + (2 × 18\pi)$
= $288 + 2\pi (72 + 18)$
= $288 + 2 × 3.14 × 90$
= $288 + 565.2$
= $853.2\ m^2$
Hence, the correct answer is 853.2.
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