A steady current element of 10e-3 az A/m is located at the origin in free space. Find the magnetic field intensity dH at a point (1,0,0)
Answer (1)
19th Mar, 2021
Hello candidate,
The magnitude of Magnetic field intensity refers to the number of ampere turns which the the electric or the the conducting coil makes on a unit length to produce a magnetic effect on a solenoid or any other magnetic body.
Hence, the value of magnetic field intensity is equal to current element multiplied by the space coordinates, which gives 10e^-3 *(0+0+1)= 10e^-3 H.
Hope it was helpful!!
Comments (0)
Related Questions
Trending Articles/News
![CAT Result 2025: Release Date, Scorecard Download [Direct Link] iimcat.ac.in, Percentile Calculation & Cutoffs](https://cache.careers360.mobi/media/presets/50X50/article_images/2025/11/21/CAT Result Date 2025.jpg)
