Question : Directions: The following figure shows the number of students (in thousands) admitted and passed out per year in a college during the years 2000-2004. Follow the figure and answer the question.
The ratio of the number of students admitted in the year 2002 to the average of the number of students passed out in the years 2003 and 2004:
Option 1: $7:8$
Option 2: $8:9$
Option 3: $9:8$
Option 4: $8:7$
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Correct Answer: $8:9$
Solution :
As per the given graph:
The number of students admitted in the year 2002 = 8 thousand
The total number of students who passed out in the years 2003 and 2004 = (9 + 9) = 18 thousand
Number of given years = 2
The average of the number of students passed out in the years 2003 and 2004 = $\frac{18}{2}$ = 9 thousand
Required ratio = $\frac{\text{The number of students admitted in the year 2002}}{\text{The average of the number of students passed out in the years 2003 and 2004}}$
Required ratio = $8:9$
Hence, the correct answer is $8:9$.
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