find the cube root of 8i, expressing each in the form of a+ib
Answer (1)
11th Apr, 2020
Hey!
Please find the answer to your query here:
First of all, we will write 8i in polar form.
8i= (2^3) (cos pi/2 + i.sin pi/2)
The cube roots are: 2(cos pi/6+ i.sin Pi/6), 2(cos (pi/6+ 2pi/3)+ i.sin (pi/6+ 2pi/3)) and 2(cos (pi/6+ 4pi/3)+ i.sin (pi/6+ 4pi/3)).
Therefore, these roots are [sqrt(3)+i], [-sqrt(3)+i], [-2i]
Hope this answer helps!
Comments (0)
Related Questions
How to find cube root with ease??
80 Views
What is the cube root of 3540?
14 Views
What is the Cube Root of 1999?
18 Views
What is the cube root of 88?
20 Views
Trending Articles/News
.jpg)
