Formation of real image using a biconvex lens is shown below : If the whole set up is immersed in water without disturbing the object and the screen positions , what will one observe on the screen ?
Hello! The answer to this is that the image will disappear . We know that
1/f=(u2/u1 - 1)(1/R1 - 1/R2)
where u1= refractive index of medium of object
u2= refractive index of lens
and R1 and R2 are the radius of curvature of the two surfaces of lens.
We know that:
1/f= 1/v - 1/u and also
1/f= (Ureal - 1)(1/R1 - 1/R2)
where Ureal= refractive index in which the set up is kept.
Now, when we immerse the whole apparatus in water then Ureal changes and as you changes f also changes. Now, the value of u will be same but f changes so the value of v also changes but the SCREEN IS KEPT AT THE SAME DISTANCE AS BEFORE so the image will not coincide on the screen and it will disappear.
Hope the answer helps.
Related Questions
Know More about
Symbiosis Entrance Test
Eligibility | Application | Admit Card | Result | Preparation Tips | Exam Pattern | Selection Process
Get Updates Brochure
Your Symbiosis Entrance Test brochure has been successfully mailed to your registered email id “”.
