Question : If a and b are the lengths of the sides of a right triangle whose hypotenuse is 10 units and whose area is 20 sq. units, then the value of $(a+b)^{2}$ is:
Option 1: 140
Option 2: 180
Option 3: 120
Option 4: 160
Correct Answer: 180
Solution :
Given that the area of the right angle triangle is 20 sq. units and the hypotenuse is 10 units.
The area of a right triangle,
$⇒ \frac{1}{2} \times a \times b = 20$
$⇒ab=40$
Applying Pythagoras theorem,
$10^{2} = a^{2} + b^{2}$
⇒ $100 = a^{2} + b^{2}$
$ \therefore (a+b)^{2} = a^{2} + b^{2} +2ab$
$ (a+b)^{2} = 100 +2(40)= 100 + 80 = 180$
Hence, the correct answer is 180.
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