Question : If P is circumcentre in $\triangle$ ABC, $\angle$BPC = $30^{\circ}$, what is the value (in degrees) of $\angle$BAC ?
Option 1: 15
Option 2: 60
Option 3: 75
Option 4: 105
Correct Answer: 15
Solution :
The angle subtended by any chord of a circle at the centre of a circle is twice the angle subtended at the major arc by the same chord.
$\angle$BAC = $\frac{1}{2} \angle$BPC
= $\frac{1}{2}×30^{\circ}$
= $15^{\circ}$
Hence, the correct answer is 15.
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