Question : If r is the remainder when each of 4749, 5601, and 7092 is divided by the greatest possible number d(>1), then the value of (d + r) will be:
Option 1: 276
Option 2: 282
Option 3: 298
Option 4: 271
Answer (1)
15th Jan, 2024
Correct Answer: 276
Solution :
According to the question,
d = HCF of (5601– 4749) and (7092 – 5601)
= HCF of 852 and 1491
= 213
So, r = remainder [$\frac{4749}{213}$] = 63
The sum of (d + r) = 213 + 63 = 276
Hence, the correct answer is 276.
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