if the de Broglie wavelength of the electron in nth Bohr orbit are hydrogenic atom is equal to 1.5 pi a there the value of n by z
Hii,
The solution of this is:
2πr = nλ
2π ao * n^2/z = n*1.5*π ao
n/z = 0.75
Hope this helps.
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Hii,
The solution of this is:
2πr = nλ
2π ao * n^2/z = n*1.5*π ao
n/z = 0.75
Hope this helps.
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