in ydse ,if the width of the slits are in the ratio of 4:9 then the ratio of intensity of Maxima to the intensity at minima will be
Answer (1)
25th Feb, 2020
Shashank, the answer to your query is 25:1 that is, the ratio of intensity of maxima to the intensity of minima is 25:1 . Now let us understand the solution of this query.
It is given that the slit widths are in ratio 4:9
Now, the width (W) is directly proportional to intensity (I), so W1/W2 = I1/I2
Therefore, we get the ratio I1/I2 = 4/9
Now, the intensity is proportional to the square of the amplitude also, so
I1/I2 = (A1)^2/ (A2)^2
So, the ratio of amplitude is A1:A2 is 2:3
Now, the intensity of maxima is (A1+A2)^2 = (2+3)^2 = 25
and the intensity of minima is (A1-A2)^2 = (2-3)^2 = 1
Therefore the ratio of intensity of maxima to that of minima is 25:1
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