Locus of a point z in argand plane satisfying |z^2 - (z')^2| = |z|^2. Re(z) is more than or equal to 0, Im(z) is more than or equal to 0
Answer (1)
10th May, 2020
This is an easy question. Just put z= x +iy then find all the parameters given in the equation. I am giving some of the parameters like z'=x-iy. Now calculate the term in LHS. Then after calculate |z|=( x^2 + y^2)^1/2. Then after equate those terms and you can easily get the locus of the curve that is given.
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