orbital having 3 angular nodes and 3 tatal nodes is
1.The angular node= l(azhimuthal quantum number).
2.Total nodes=n-1(principle quantum number).
Given: 3 angular nodes,then l=3. ; 3 Total nodes, then n-1=3.
l=3 means it is f- orbital and
n-1=3 solving this we get n=4. So 4th shell.
Finally the answer is 4f.
The number of angular nodes is given by 'l'(azimuthal quantum number) and total nodes is given by n-1. so if there are 3 angular nodes then the value of l is 3. And total nodes is n-1 which is equal to 3.
which implies n=4. l=3 represents the orbital d orbital and n=4 shows that its in 4th shell.
therefore the required orbital is 4d.