State Bohrs quantization condition of angular momentum. Calculate the shortest wavelength of the Bracket series and state to which part of the electromagnetic spectrum does it belong.
Answer (1)
23rd Apr, 2022
Hello,
Bohr’s quantization condition of angular momentum: According to Bohr electron can revolve in certain discrete orbits called stationary orbits.
For Brackett series n1 = 4 and n2 = 5 6 7… Therefore For shortest wavelength n2 = ∞. Therefore or λ 1458.5 10-9 m or 1458.5 nm.The shortest wavelength of the Brackett series is 1458.5 nm. This wavelength belongs to infrared range of electromagnetic spectrum.
Thank you.
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