the area of bolt of ink is growing such that after t second A=3r^2 + t/5+7 calculate the rate of increase of area after 5second
Answer (1)
18th Oct, 2020
Dear student,
Please you have to check once again your question, because according to me in place "r" it should be "t".
So, I am solving question by taking the question as - A=3t^2 + t/5+7
Now rate of anything wrt time is : d(anything) / dt.
Therefore the rate of area wrt time is = d(A) / dt
d(A) / dt = 6t +1/5 + 0 = 6t + 1/5.
Now therefore the rate of change (increase) of area wrr time in 5 seconds will be :-
d(A) / dt (at t = 5) = 30 + 1/5 = 151/5 = 30.2
Please you have to check once again your question, because according to me in place "r" it should be "t".
So, I am solving question by taking the question as - A=3t^2 + t/5+7
Now rate of anything wrt time is : d(anything) / dt.
Therefore the rate of area wrt time is = d(A) / dt
d(A) / dt = 6t +1/5 + 0 = 6t + 1/5.
Now therefore the rate of change (increase) of area wrr time in 5 seconds will be :-
d(A) / dt (at t = 5) = 30 + 1/5 = 151/5 = 30.2
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