Question : The average of nine consecutive numbers is $n$, if the next two numbers are also included the new average will be:
Option 1: increase by 2
Option 2: remain the same
Option 3: increase by 1.5
Option 4: increase by 1

Question

Question : The average of nine consecutive numbers is $n$, if the next two numbers are also included the new average will be:

Option 1: increase by 2

Option 2: remain the same

Option 3: increase by 1.5

Option 4: increase by 1

Team Careers360 · Accepted Answer

Correct Answer: increase by 1

Solution : Given: The average of nine consecutive numbers is $n$.
So, fifth number = $n$
Tenth number = $n + 5$
Eleventh number = $n + 6$
$ herefore$ New average = $\frac{9n + n + 5 + n + 6}{11}=\frac{(11n+11)}{11} = \frac{(n+1) imes 11}{11} = (n+1)$
Hence, the correct answer is "increases by 1".

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Question : The average of nine consecutive numbers is n, if the next two numbers are also included the new average will be:Option 1: increase by 2Option 2: remain the sameOption 3: increase by 1.5Option 4: increase by 1

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Question : The average of nine consecutive numbers is $n$ , if the next two numbers are also included the new average will be:
Option 1: increase by 2
Option 2: remain the same
Option 3: increase by 1.5
Option 4: increase by 1