the centre of the circle lies on the line x+y=2 in the first quadrant then the diameter is
hello manish
i think you have provided a wrong question as this line is passing through (2,0) and (0,2) in the first quadrant and a circle of any radius can be drawn by taking a centre at the given line . however if the line which makes the crossection between x and y axis is taken s the diameter then its length would be 8^1/2 ( underroot 8 ) by using pythagorus theorem .you ask this question on other plateforms also like doubtnut or instasolve