Question : Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Then the maximum capacity of a container that can measure the diesel of the three containers an exact number of times is:
Option 1: 31 litres
Option 2: 62 litres
Option 3: 41 litres
Option 4: 84 litres
Correct Answer: 31 litres
Solution :
To determine the maximum capacity, we need to find the HCF of 403, 434 and 465.
The prime factors of 403, 434 and 465 are:
⇒ 403 = 13 × 31
⇒ 434 = 2 × 7 × 31
⇒ 465 = 3 × 5 × 31
The HCF of 403, 434 and 465 is 31.
Therefore, the maximum capacity of a container that can measure the diesel of the three containers an exact number of times is 31.
Hence, the correct answer is 31 litres.
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